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Oliga [24]
3 years ago
14

Find three consecutive integers whose sum is 60.

Mathematics
2 answers:
alexandr1967 [171]3 years ago
7 0

60 = x + x + 1 + x + 2

60 = 3x + 3

-3

57 = 3x

/3

19 = x

The 3 integers are: 19, 20, and 21.

Ket [755]3 years ago
6 0

Answer: 19, 20, and 21

Step-by-step explanation: This problem states that the sum of 3 consecutive integers is 60 and it asks us to find the integers.

Three consecutive integers can be represented as followed.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer</em>

X + 2 ⇒ <em>third integer</em>

Since the sum of our 3 consecutive integers is 60, we can set up an equation.

X + X + 1 + X + 2 = 60

3x + 3 = 60

      -3     -3

3x = 57

÷ 3  ÷ 3

X = 19

X + 1 = 20

X + 2 = 21

Therefore, our three consecutive integers are 19, 20, and 21.

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Find the value of k so that 48x-ky=11 and (k+2)x+16y=-19 are perpendicular lines.
Rufina [12.5K]

Answer: k = -1 +/- √769

<u>Step-by-step explanation:</u>

48x - ky = 11

<u>-48x        </u>  <u> -48x</u>

         -ky = -48x + 11

         \frac{-ky}{-k} = \frac{-48x}{-k} + \frac{11}{-k}    

           y =\frac{48x}{k} - \frac{11}{k}

Slope: \frac{48}{k}

*************************************************************************

 (k + 2)x + 16y = -19

<u>- (k + 2)x          </u>   -<u>(k + 2)x </u>

                 16y = -(k + 2)x - 19

                  \frac{16y}{16} = -\frac{(k + 2)x}{16} - \frac{19}{16}

                  y = -\frac{(k + 2)x}{16} - \frac{19}{16}

Slope: -\frac{(k + 2)}{16}

**********************************************************************************

\frac{48}{k} and -\frac{(k + 2)}{16} are perpendicular so they have opposite signs and are reciprocals of each other.  When multiplied by its reciprocal, their product equals -1.

-\frac{(k + 2)}{16} *  \frac{k}{48} = -1

\frac{(k + 2)k}{16(48)} = 1

Cross multiply, then solve for the variable.

(k + 2)(k) = 16(48)

k² + 2k - 768 = 0

Use quadratic formula to solve:

k = -1 +/- √769



5 0
4 years ago
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