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e-lub [12.9K]
3 years ago
6

One of the factors of the polynomial x3 + 5x2 + 6x is (x2 + 3x). What is the other factor?

Mathematics
1 answer:
butalik [34]3 years ago
8 0

Answer:

x+2

Step-by-step explanation:

Dividing the poly by the known factor:

x3+5x2+6x    <u>| x2+3x</u>

-x3-3x2             x + 2  <- the answer is here

      2x2+6x

      -2x2-6x

To prove that, let's multiply the two factors and find the pylonomial back on:

(x2+3x).(x+2) = x3 + 2x2 + 3x2 + 6x = x3 + 5x2 + 6x

Tks your attention!

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Una fábrica envasadora recibe diariamente distintos tipos de aceite en las siguientes cantidades: 195 l, 275 l, 315 l, 460 l y 5
BabaBlast [244]

Answer:

Se calcula el maximo comun divisor.

195/5 = 39

275/5 =55

315/5 =63

460/5= 92

525/5 =105

Se deben utilizar 354 garrafas

Step-by-step explanation:

Descomponemos cada número en factores primos.

Después, señalamos los factores comunes.

A continuación, en cada uno de los comunes, escogemos el factor con menor exponente.

Y por ultimo, multiplicamos los factores elegidos.

195 3 275 5 315 3 460 2 525 3

65 5 55 5 105 3 230 2 175 5

13 13 11 11 35 5 115 5 35 5

1  1  7 7 23 23   7 7

   1   1    1  

3 0
3 years ago
Solve the system of linear equations by substitution 2x-y=6 x=y-1
Oksana_A [137]

substitute x for y-1
2(y-1)-y=6 distribute
2y-2-y=6 subtract y in 2y
y-2=6 add 2 to get y by itself
y=8

Put y back into equation x=y-1
x=8-1
X=7
6 0
3 years ago
An automobile manufacturer is concerned about a possible recall of its best selling four-door sedan. If there was a recall there
goldfiish [28.3K]

Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

(a) What is the probability that the defect is the brakes or the fueling system if the probability of defects in both systems simultaneously is 0.15?

(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

P(T) = 0.18

P(F) = 0.17

P(O) = 0.40

A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

P(B' ⋃ F') = 0.73

7 0
3 years ago
Graph f(x) = 2x^4+3 <br> let x = 0, 1, and 2.<br> please show your work
mestny [16]
Sub those points for x
f(x) is the y

(x,y)

so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint

for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point

for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point


points are
(0,3)
(1,5)
(2,35)
3 0
3 years ago
A box was 3/4 full of marbles. The box fell on the floor. Thirty marbles fell out. This was 20% of the marbles in the box. How m
Hunter-Best [27]

Answer: -5.7

Step-by-step explanation:

3/4- 30= -29.25 and that was only 20% of the box that was dropped out of the box. -29.25 of 20% equals -5.85. 3/4 of 20% equals 0.15 subtract the 2 decimals and you will get -5.7

7 0
3 years ago
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