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bulgar [2K]
3 years ago
12

Really just free points, should be easy

Mathematics
2 answers:
Lostsunrise [7]3 years ago
6 0
Hope this helps you..!!!

Maksim231197 [3]3 years ago
3 0

15 - 2(- 13s + 3) = 9s - 9 + 16s

15 + 26s - 6 = 25s - 9

9 + 26s = 25s - 9

26s - 25s = -9 - 9

s = - 18

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Use the figure and find LN, if LM=6x and MN=2x+12
Alexus [3.1K]

Answer:

LN

= LM + MN

= 6x + 2x + 12

= 8x + 12

5 0
3 years ago
Vertex A in quadrilateral ABCD lies at (-3, 2). If you rotate ABCD 180° clockwise about the origin, what will be the coordinates
Marysya12 [62]
I think it might be B hope I’m right
3 0
4 years ago
Read 2 more answers
How do I solve this equation? I need a refresher on Algebra.
yaroslaw [1]
These equations seem tricky, but aren't as hard as you think. Just solve it like you are regularly adding fractions.

Your common denominator is 9x + 9, so

1/(9x+9)  =  36/(9x + 9)   -    (5x + 5)/9

1 - 36 + 5x + 5 / 9x - 9
30x - 30/9x - 9
10x-10/3x - 3
10(x-1)/3(x-1)
10/3

Hope this helped!
5 0
3 years ago
Solve for y. 8y -11y – -2 = -16 y =
polet [3.4K]
8y - 11y - -2 = -16
-3y + 2 = -16
-3y = -16 - 2 = -18
y = -18/-3 = 6
y = 6
5 0
3 years ago
X + y =125<br> 5x + 8y = 775
muminat

Answer:

x=75, y = 50

Step-by-step explanation:

Solve the following system:

{x + y = 125 | (equation 1)

5 x + 8 y = 775 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 8 y = 775 | (equation 1)

x + y = 125 | (equation 2)

Subtract 1/5 × (equation 1) from equation 2:

{5 x + 8 y = 775 | (equation 1)

0 x - (3 y)/5 = -30 | (equation 2)

Multiply equation 2 by -5/3:

{5 x + 8 y = 775 | (equation 1)

0 x+y = 50 | (equation 2)

Subtract 8 × (equation 2) from equation 1:

{5 x+0 y = 375 | (equation 1)

0 x+y = 50 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 75 | (equation 1)

0 x+y = 50 | (equation 2)

Collect results:

Answer:  {x = 75 , y = 50

8 0
3 years ago
Read 2 more answers
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