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Zigmanuir [339]
3 years ago
13

There are 399 items advertised in a catalog. If the catalog is 75 pages long, what is the average number of items per page?

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0

Answer:

Step-by-step explanation:

Well, we can divide 399 and 75 so it would be 5.32. Round that and it would be about 5 items per page

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the number of women at a training workshop was two less than three times the number of men if 50 people attended the workshop ho
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Answer: 148

Work: 50 men multiplied by 3 =150
If there is two less women from 3 multiplied by 50 (150) , then 150 - 2 = 148
6 0
3 years ago
A number k is greater than 3. Which of thefollowing is true about k over 3 ?​
FrozenT [24]

Well, there is nothing following, but if there is anything about K equal to or greater 4, or K being>2 than thats it.

4 0
3 years ago
A hallway measuring 90 feet x 7 feet requires 1/2 a fluid ounce of cleaning solution per square foot. How much cleaning solution
Vilka [71]
315 fluid ounces of solution
7 0
3 years ago
The sum of two numbers is 47 and the difference is 25 . what are the numbers?
taurus [48]
The numbers are:  36 and 11 .
______________________________________________
Explanation:
______________________________________________
Let us represent the TWO (2) numbers with the variables;
         "x" and "y" .
__________________________________________
     x + y = 47 .

     y − x = 25.
__________________________________________
Since:  " y − x = 25 " ;

Solve for "y" in terms of "x" ;

  y − x = 25  ;

Add "x" to each side of the equation:
_____________________________________________
   y − x + x  = 25 + x  ;

to get:

   y = 25 + x .

Now, since:

  x + y = 47 ;

Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :

x + (25 + x) = 47  ;

x + 25 + x + 47 ;

2x + 25 = 47 ;

Subtract "25" from each side of the equation:

2x + 25 − 25 = 47 − 25 ;

2x  = 22  ;

Divide EACH SIDE of the equation by "2" ;
 to isolate "x" on one side of the equation; and to solve for "x" ; 
 
2x / 2 = 22 / 2 ;

    x = 11 ;
______________________________________________
x + y = 47<span> ;

</span>Plug in "11" for "x" into the equation ; to solve for "y" ;

11 + y = 47 ;

Subtract "11" from EACH SIDE of the equation;
  to isolate "y" on one side of the equation; and to solve for "y" ;

 11 + y − 11 =  47 − 11  ;

            y = 36 .
___________________________________________
So:  x = 11 , y = 36 ;
___________________________________________
 Let us check our work:

y − x = 25 ;

36 − 11 =? 25 ?  Yes!

x + y = 47 ;

36 + 11 =? 47 ? Yes!
______________________________________________
The numbers are:  36 and 11 .
______________________________________________
5 0
3 years ago
The hypotenuse of a right triangle is 10 ft long. the shorter leg is 2ft shorter than the longer leg. find the side lengths of t
Gwar [14]
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Our first piece of information is that our shorter leg (s) is 2 feet shorter than our longer leg (l). This can be written as s=l-2.
Our second piece of information is that using the Pythagorean theorem that our shorter leg squared plus our longer leg squared is equal to our hypotenuse squared. This can be represented by s^2+l^2=10^2. Now we can solve.
We have already isolated for s in our first equation, so we can substitute l-2 in.
(l-2)^2+l^2=10^2
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l=6
Now we can substitute in for s in our simpler equation
s=6-2
s=4
We now know that using our knowledge of systems of equations, the side lengths of this right angle triangle are 6 and 4.
5 0
3 years ago
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