Answer all of the questions
1 answer:
You might be interested in
Answer:
a)The company has to 250 cameras in one day to equal its daily cost
b)Their daily profit will be $400
Step-by-step explanation:
Given:
overhead expenses = $1500
labour and materials expenses = $9
cameras sell for $15 each
To Find:
(a)How many cameras must the company sell in one day to equal its daily cost
(b) If the manufacturer can increase production by 50 cameras per day, what would their daily profit be?
Solution:
a) let the number of cameras sold per day be x
Total daily cost = overhead expenses +labour and materials expenses
Total daily cost = 1500 + 9x--------------------------(1)
Total daily revenue = 15x------------------------------(2)
Equating (1) and (2)
1500 + 9x = 15x
1500 = 15x- 9x
1500 = 6x
x=
x= 250
So, the company has to 250 cameras in one day to equal its daily cost.
b) increasing production by 50 cameras per day will give a daily profit of
=>50 X (17-9)
=>50 X 8
=> 400
Answer:
Step-by-step explanation:
Given the system of equations:
2x + 3y = 15
X + 3y = 0
What is x?
2x + 3y = 15
X + 3y = 0 subtract the bottom equation fron the top one
2x - x + 3y - 3y = 15 - 0 see how the 3y - 3y equates to zero
2x - x = 15
x = 15 Now for extra credit what is y?
X + 3y = 0
15 + 3y = 0
15 - 15 + 3y = 0 - 15
3y = -15
3y/3 = -15/3
y = -5
-15
-5
0
5
15
