Given:
Point P divides the line segment AB in 5:3 where A(-6,9) and B(2,1).
To find:
The coordinates of point P.
Solution:
Section formula: If a point divide a line segment in m:n, then the coordinates of point are
Point P divides the line segment AB in 5:3 where A(-6,9) and B(2,1). Using section formula, we get
Therefore, the coordinates of point P are (-1,4).
Answer:
-1
Step-by-step explanation:
-4+-1+0+1=-4
4 divided by -4 = -1
To transform the left side of the equation into the right side under the interval (0 < θ < π/2), the missing trigonometric identity to complete the equation is cos2 θ = 1- sin2 θ. This is a trigonometric identity specifically under the <span>Pythagorean Identities</span>
Ans:
The solve for x:
2.41x+3.65(248-x)=622.48
2.41x+3.65×248-3.65x=622.48
2.41x-3.65x+905.2=622.48
-1.24x=622.48-905.2
-1.24x= -282.72
x= -282.72÷ -1.24
x=228
Pounds of nuts nper pound $2.41should be included:
228× $2.41
=549.48
Hope it Helps!
Answer: <FED , <DFE , <EDF
Step-by-step explanation:
