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Aloiza [94]
3 years ago
13

What is the measure of x

Mathematics
2 answers:
mixer [17]3 years ago
8 0

Answer:

x=76 degrees

Step-by-step explanation:

< dij + < jih = 180   straight line

< dij + 107 = 180

subtract 107 from each side

< dij = 73


<jdi + < dij + <idj = 180  triangle

31 + 73 + < idj = 180

combine like terms

104+ < idj = 180

subtract 104 from each side

< idj = 76

<idj = < ajf   vertical angles

76 < ajf

<ajf = x

x=76 degrees


Radda [10]3 years ago
4 0
The answer is 76 the answer is 76 degrees
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Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

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Plugging our values into the equation, we get

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as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

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x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

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