I’m stuck on this problem plz help
1 answer:
You might be interested in
Answer:
1) The windsurfer is approximately 580 ft from each lifeguard stand.
2) The distance between the Earth and Mercury is approximately 61 million miles.
Step-by-step explanation:
The image other two situations described is presented in the attached image to this answer.
1) From the attached image, the windsurfer forms a right angled triangle with each of the lifeguard stand and the midpoint between the two lifeguard stands.
Hence, the angle at the top of the triangle is half of 30°, 15° and the distance from the midpoint of the lifeguard stands to the lifeguard stands is 300/2 = 150 ft.
Let the required distance of the windsurfer from each of the lifeguard stands be x.
Using trigonometric relations,
Sin 15° = (150/x)
x = 150 ÷ sin 15° = 150 ÷ 0.2588
x = 579.6 ft = 580 ft to the nearest whole number
2) From the image, the Sun, Earth and Mercury form a triangle.
Let the possible distance between the Earth and Mercury be y.
Using cosine rule,
y² = 36² + 93² - (2×36×93×cos 22°)
y² = 3,736.5769098208
y = √3,736.5769098208 = 61.13 million miles = 61 million miles to the nearest million miles.
Hope this Helps!!!
