If this paper dosent help u solve it on Your own i can walk u through it
I think the answer is 78.
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
This is true because octa- means 8
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Answer:
cot(θ) = 4/5
Step-by-step explanation:
In the polar/rectangular coordinate representation (x, y) ⇔ (r; θ), we know that ...
(x, y) = (r·cos(θ), r·sin(θ))
From the various trig definitions and identities, we also know that ...
cot(θ) = cos(θ)/sin(θ) = (x/r)/(y/r) = x/y
For the given (x, y) = (-4, -5), the cotangent is ...
cot(θ) = -4/-5 = 4/5