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Len [333]
4 years ago
13

Patrycia’s overall grade in her physics class is based solely on the average of her scores on 6 unit tests. The grade she receiv

ed on the first 5 tests are as follows: 89, 93, 95, 92, 90. What grade does Patrycia need to earn on her 6th unit test to end up with a 90% in the class?
A.
76.5%
B.
81%
C.
90%
D.
92.5%
Mathematics
2 answers:
Sedbober [7]4 years ago
8 0
(89 + 93 + 95 + 92 + 90 + x)/6 = 90%
(459 + x)/6 = 90% (multiply by 6)
459 + x = 540
x = 540 - 459
x = 81

check...
(459 + 81)/6 = 90%
540/6 = 90%
90% = 90% (correct)

She would need to have an 81
tia_tia [17]4 years ago
3 0
It would be B. 81%

I tested out each answer by finding the average:
89 + 93 + 95 + 92 + 90 + 81 = 540
540 / 6 = 90

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8 0
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Question below
Ksivusya [100]

Answer:

m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]

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\implies m=3 \times \dfrac{3}{2}

\implies m=\dfrac{9}{2}

<u>Calculate the value of H</u>

Given:

\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)

Therefore:

\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />

<u>Calculating m × H</u>

<u />

<u />\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]

\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]<u />

7 0
2 years ago
westfalls is 7 miles south of edenville and concord is 13 miles west of westfalls. what is the distance from edenville to concor
jok3333 [9.3K]

Answer:

The distance from Endnville to Concord = 14.8 miles

Step-by-step explanation:

∵ Westfalls is 7 miles South of Endnville

∵ Concord is 13 miles West of Westfalls

∵ South and West are ⊥

∴ The distance from Endnville to Concord = √(7)² + (13)²

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7 0
3 years ago
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BigorU [14]

Answer:

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8 0
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Harlamova29_29 [7]

Answer:

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Step-by-step explanation:

2/8 or 1/4 because the spots on the spinner are blue out of 8 is 2/8 or 1/4

3 0
3 years ago
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