To find all of the feet of pipe that Brad has, you add both of the lengths of the pipes together. So 2 5/12+3 7/12. Add the numbers together first, 5. Then add the fractions, 5/12+7/12=1. So add 5 and 1 and you get 6 feet of pipe. Hope this helps.
Answer:
1) 2
2) 3
3) 4
4) 5
Step-by-step explanation:
Plug in the c variables in the table into the equation to find w.
<h3>
Answer: Choice H) 2</h3>
=============================================
Explanation:
Recall that the pythagorean trig identity is 
If we were to isolate sine, then,

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.
Through similar calculations,
Cosine is also positive in this quadrant.
-------------
So,

Therefore,

is an identity as long as 0 < x < pi/2
Answer:
1.) SAS | 2.) HL | 3.) HL | 4.) SSS (Not too sure about this one)
Step-by-step explanation:
Is there a picture of the data set? I cannot give you an exact answer without the actual data values, but I can explain how to solve it.
The mean absolute deviation basically tells the average of how much each data value deviates from the mean of the entire data set. Therefore you just find the difference between each value in the data set and 57. Then you take all the differences and find the average by adding them all up and dividing by the number of values.