We have the parabola with equation y = 4x².
We have to determine the shape and direction of it.
If we compare it to the standard equation y = ax² + bx + c, we can see that a = 4, b = 0 and c = 0.
As the value of a is positive, the parabola will open upward.
The parameter has an absolute value greater than 1. This means that y increases "faster" relative to x that a parabola with a = 1.
This means that the parabola will be narrow about its line of symmetry which we call vertical strecth.
Answer:
Because a is positive the parabola opens upward.
Because a has an absolute value larger than 1 the parabola is narrow about its line of symmetry which we call vertical stretch.
<u><em>Explanation</em></u>: The reason why is because when divide 10/60 it becomes a decimals and cans can't be decimals, but if you divide 60/10 then it will be 6 cans in each row.
10* (1/5)
= 10/5
= 2
The final answer is 2~
First you need to find the mean & median:
mean:
93 + 91 + 98 + 100 + 95 + 92 + 96 = 665
665 / 7 = 95
median:
<u>91</u>, <em>92</em>, <u>93</u>, 95, <u>96</u>, <em>98</em>, <u>100</u>
95
Because the mean and median are the same, her next test score should be 95. The average of the current average and 95 (her next test score) is 95, so that will remain the same. If you add 95 to the median list,the median will still be 95. The same goes for the mean.Her next test score should be 95.
Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
