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2 years ago

Please help me find the answer

Mathematics

1 answer:

m_a_m_a [10]2 years ago

6 0

Answer:

ok then

Step-by-step explanation:

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The hourly wage of workers was raised from $11.50 to 13.67 in 7 years

neonofarm [45]

Answer:

$13.67 - $11.50

So the raise over 7 years was $2.17

So to find the annual raise in the wage:

$2.17 / 7 = 0.31

His wage was raised <u>.31 every year</u>.

6 0

2 years ago

0.04x -0.06y=0.48<br> 0.08x-0.11 y=0.92

UkoKoshka [18]

Answer:

0.04x -0.06y=0.48

x = 1.5y + 12

0.08x-0.11 y=0.92

x = 1.375y + 11.5

Hope this helps!

6 0

2 years ago

Please help me brainliest for you :)

Sati [7]

Answer:

single digit, for example= 6

interger power of 10 =10^8

Step-by-step explanation:

it will be written as

6*10^8

spoken as: six time 10 rais to the power of 8

5 0

2 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$