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loris [4]
3 years ago
15

Complete the square for 3x^2-12x=9

Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

The solutions are -0.65 and 4.65.

Step-by-step explanation:

3x^2 - 12x = 9

Divide both sides by 3

x^2 - 4x = 3

To make a square with "x^2 - 4x", you need to have a "+ 4" after it so it can be simplified as (x-2)^2.  So add 4 to both sides.

x^2 - 4x + 4 = 7

(x-2)^2 = 7

x - 2 = (square root) of 7

x = 2 (+/-) (square root) of 7.

x = {-0.65, 4.65}

The solutions are -0.65 and 4.65.

hope this helps:)sorry if it doesnt

VikaD [51]3 years ago
6 0

Answer:

(x-2)^2=7

Step-by-step explanation:

We have been given an equation 3x^2-12x=9. We are asked to complete the square for the given equation.

We know that when an equation is in form x^2+bx=c, then we will add (\frac{b}{2})^2 to both sides of equation to make a perfect square.

Dividing both sides by 3, we will get:

x^2-4x=3

Add (\frac{b}{2})^2 on both sides of equation:

(\frac{b}{2})^2=(\frac{4}{2})^2=2^2=4

x^2-4x+4=3+4

x^2-4x+4=7

Now, apply perfect square formula a^2-2ab+b^2=(a-b)^2:

(x-2)^2=7

Therefore, our required equation would be (x-2)^2=7.

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
How to find slope and y intercept from the equation ax+by=c?
melisa1 [442]

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3 years ago
I really need help with this question
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Answer:

39

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I assume the father's age is a 2-digit number. He is not 9 years old or younger, and he is not 100 years old or older.

The sum of the digits of a two-digit number goes up by 1 from one number to the next unless the number ends in 9.

For example, from 17 to 18, the sum of the digits goes from 8 to 9.

If the number ends in 9, for example, 29, the digits add to 11. Then the next number is 30, and now the sum of the digits is 3, which is less than 11.

The father's age now is a number whose sum of digits is not only greater than the sum of the digits next year, but it is 3 times greater.

Let's look at 2-digit number and the next number and the sum of their digits.

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