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loris [4]
3 years ago
15

Complete the square for 3x^2-12x=9

Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

The solutions are -0.65 and 4.65.

Step-by-step explanation:

3x^2 - 12x = 9

Divide both sides by 3

x^2 - 4x = 3

To make a square with "x^2 - 4x", you need to have a "+ 4" after it so it can be simplified as (x-2)^2.  So add 4 to both sides.

x^2 - 4x + 4 = 7

(x-2)^2 = 7

x - 2 = (square root) of 7

x = 2 (+/-) (square root) of 7.

x = {-0.65, 4.65}

The solutions are -0.65 and 4.65.

hope this helps:)sorry if it doesnt

VikaD [51]3 years ago
6 0

Answer:

(x-2)^2=7

Step-by-step explanation:

We have been given an equation 3x^2-12x=9. We are asked to complete the square for the given equation.

We know that when an equation is in form x^2+bx=c, then we will add (\frac{b}{2})^2 to both sides of equation to make a perfect square.

Dividing both sides by 3, we will get:

x^2-4x=3

Add (\frac{b}{2})^2 on both sides of equation:

(\frac{b}{2})^2=(\frac{4}{2})^2=2^2=4

x^2-4x+4=3+4

x^2-4x+4=7

Now, apply perfect square formula a^2-2ab+b^2=(a-b)^2:

(x-2)^2=7

Therefore, our required equation would be (x-2)^2=7.

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kherson [118]

Answer:

\large\boxed{(x-2)^2+(y-1)^2=34}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

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The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

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3 years ago
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Step-by-step explanation

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alexgriva [62]

Answer:

Step-by-step explanation:

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