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loris [4]
3 years ago
15

Complete the square for 3x^2-12x=9

Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

The solutions are -0.65 and 4.65.

Step-by-step explanation:

3x^2 - 12x = 9

Divide both sides by 3

x^2 - 4x = 3

To make a square with "x^2 - 4x", you need to have a "+ 4" after it so it can be simplified as (x-2)^2.  So add 4 to both sides.

x^2 - 4x + 4 = 7

(x-2)^2 = 7

x - 2 = (square root) of 7

x = 2 (+/-) (square root) of 7.

x = {-0.65, 4.65}

The solutions are -0.65 and 4.65.

hope this helps:)sorry if it doesnt

VikaD [51]3 years ago
6 0

Answer:

(x-2)^2=7

Step-by-step explanation:

We have been given an equation 3x^2-12x=9. We are asked to complete the square for the given equation.

We know that when an equation is in form x^2+bx=c, then we will add (\frac{b}{2})^2 to both sides of equation to make a perfect square.

Dividing both sides by 3, we will get:

x^2-4x=3

Add (\frac{b}{2})^2 on both sides of equation:

(\frac{b}{2})^2=(\frac{4}{2})^2=2^2=4

x^2-4x+4=3+4

x^2-4x+4=7

Now, apply perfect square formula a^2-2ab+b^2=(a-b)^2:

(x-2)^2=7

Therefore, our required equation would be (x-2)^2=7.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

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Answer:

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Step-by-step explanation:

List out the factors of each

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60: 1,2,3,4,5,6,10,12,15,20,30,60

the highest number they both have in common is 12

8 0
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