The answer would be B. symmetric property
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
Solve for h:V = π h r^2
V = h π r^2 is equivalent to h π r^2 = V:π h r^2 = V
Divide both sides by π r^2:
Answer: h = V/(π r^2)
Answer:
DONT KNOW TO BE HONEST SEVRS ARE SWAMPED
Step-by-step explanation:
Answer:
970m^{2}
Step-by-step explanation:
This polygon can be divided in two figures: one is a triangle, an the other one is a square.
We'll begin calculating the triangle's area, using the following formula:
Where:
As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.
Now we are going to calculate the square's area, that is much more simple:
Where:
To know the whole figure's area, we add up both areas:
