D=4q
25q+10d=195
5q+2d=39
sub 4q foro d
5q+2(4q)=39
5q+8q=39
13q=39
divide 13
q=3
d=4q
d=4(3)
d=12
12 dimes
3 quarters
Answer:
Option A:
x^2 + (y - 2)^2 = 9
Step-by-step explanation:
We know that the equation for a circle centered in the point (a, b) and of radius R is given by:
(x - a)^2 + (y - b)^2 = R^2
So the first thing we need to find is the center of the circle.
We can see that the center is at:
x = 0
y = 2
Then the center is at the point (0, 2)
Now we want our circle to pass through point 2, located at a distance of 2 units from the radius of the first circle.
So the distance between the center and point 2 is 2 units plus the radius of the smaller circle:
And the radius of the smaller circle is one unit.
Then, the radius of a circle centered at (0, 2) that passes through point 2 is:
R = 1 + 2 = 3
Then we have a circle centered at (0, 2) and of radius R = 3
Replacing these in the equation for a circle we get:
(x - 0)^2 + (y - 2)^2 = 3^2
x^2 + (y - 2)^2 = 9
The correct option is A
Answer:
.
Step-by-step explanation:
Answer:
<h2>1/7</h2>
Step-by-step explanation:
If I choose a number from the integers 1 to 25, the total number of integers I can pick is the total outcome which is 25. n(U) = 25
Let the probability that the number chosen at random is a multiple of 6 be P(A) and the probability that the number chosen at random is is larger than 18 be P(B)
P(A) = P(multiple of 6)
P(B) = P(number larger than 18)
A = {6, 12, 18, 24}
B = {19, 20, 21, 22, 23, 24, 25}
The conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is expressed as P(A|B).
P(A|B) = P(A∩B)/P(B)
Since probability = expected outcome/total outcome
A∩B = {24}
n(A∩B) = 1
P(A∩B) = n(A∩B)/n(U)
P(A∩B) = 1/25
Given B = {19, 20, 21, 22, 23, 24, 25}.
n(B) = 7
p(B) = n(B)/n(U)
p(B) = 7/25
Since P(A|B) = P(A∩B)/P(B)
P(A|B) = (1/25)/(7/24)
P(A|B) = 1/25*25/7
P(A|B) = 1/7
<em></em>
<em>Hence the conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is 1/7</em>
