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kozerog [31]
3 years ago
5

I think the answer Is A & C, What do you think the answer is, please hurry.

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0
Yes... indeed it is 1/8 because


125/1000 In simplest form is 1/8
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One side of a rectangle is five times as long as the other side. If the perimeter is 72 meters, what is the length of the shorte
Yakvenalex [24]
6 meters

72 = x+x+5x+5x
72 = 12x
6 = x 
the shorter side is 6 meters
3 0
4 years ago
Read 2 more answers
If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplyin
kirill115 [55]

No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.

Consider polynomial equations x^2 = 3 and x^2 = 1.

Obviously they have real solutions.

Subtract the two polynomial equations:

(x^2 - x^2) = (3 - 1)

0 = 2...

We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.

Obviously 0 = 2 has no real solution.

3 0
3 years ago
Find the area of each figure. Round to the nearest hundredth where necessary.
Papessa [141]

Answer:

The answer to your question is Triangle's area = 520 in², Square's area = 576 in²

Step-by-step explanation:

Process

1.- Calculate the area of the triangle

-Find the length of the base using the Pythagorean theorem

          c² = a² + b²

-Solve for b²

          b² = c² - a²

-Substitution

          b² = 37² - 35²

-Simplification

          b² = 1369 - 1225

          b² = 144

          b = 12 in

-Find the base

          base = 2(12) = 24 in

-Find the area of the triangle

         Area = base x height / 2

-Substitution

         Area = 24 x 35 / 2

-Simplification

         Area = 420 in²

2.- Find the area of the square

Area = side x side

-Substitution

Area = 24 x 24

-Result

Area = 576 in²

   

3 0
3 years ago
For which data set is a linear regression most reasonable?
Oxana [17]

Answer:

The correct option is;

A. A set of nine data pairs with a correlation coefficient r = -0.4

Step-by-step explanation:

In statistical analysis, it is important to make use of an adequate sample size in order to arrive at a valid result. An analysis with a very small sample size can provide misleading results

When performing regression analysis it is generally accepted by researchers that each variable should have at least 10 observations.

Therefore, the data set having nine data pairs with a negative correlation of -0.4 will provide the most valid result that can then be used for generalization about the larger statistical population.

6 0
3 years ago
Read 2 more answers
Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
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