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RoseWind [281]
3 years ago
13

How to solve 1+x+x^2​

Mathematics
1 answer:
Ksju [112]3 years ago
7 0
There is no way to simplify this further, if that’s what your asking. If you are asking to the answer to the equation, I will need to know the value of x.
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Malcolm ran the 440-yard dash and the 220-yard dash at a track meet there are 3 feet in one yard how many total feet did Malcolm
masha68 [24]
1980 feet because 440+220=660 and 660 times 3 is 1980
4 0
4 years ago
Read 2 more answers
Please help me on number 4 or 6 ITS DUE RIGHT NOW
melamori03 [73]

Answer:

#6:

A: m=-\frac{2}{5}

Step-by-step explanation:

Points: (3, -5) and (-7, -1)

Slope Formula: m=\frac{y_{2} - y_{1} }{x_{2} -x_{1} }

m = \frac{-5+1}{3-(-7)}

m = -\frac{4}{10}

m =- \frac{2}{5}

6 0
3 years ago
V=1/3nr^2h ; solve for r
sertanlavr [38]

Answer: r=3v/2nh

Step-by-step explanation:

3 0
3 years ago
What’s the inverse of y=4x^2-2
slavikrds [6]
Interchange the x and y and solve for the resulting y.
x = 4y^2 - 2
(x + 2) = 4y^2
(x + 2)/4 = y^2
+/- sqrt(x + 2)/2 = y

The graph of these two is below.

The original is in red
The inverse is in blue and green

8 0
3 years ago
There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e
notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

P_{1}=\frac{7 \ girls}{9 \ students}

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

P_{2}=\frac{6 \ girls}{8 \ students}

Then, the probability of the third girl:

P_{3}=\frac{5 \ girls}{7 \ students}

The fourth girl probability:

P_{3}=\frac{4 \ girls}{6 \ students}

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \  28\%)

Therefore, there's 28% probability that every student in the group is a girl.

5 0
3 years ago
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