Prove that the diagonals of a parallelogram bisect each other. The midpoints are the same point, so the diagonals _____
1 answer:
Answer:
Below
Step-by-step explanation:
To prove that the diagonals bisect each other we should prove that they have a common point.
From the graph we notice that this point is E.
ABCD is a paralellogram, so E is the midpoint of both diagonals.
●●●●●●●●●●●●●●●●●●●●●●●●
Let's start with AC.
● A(0,0)
● C(2a+2b,2c)
● E( (2a+2b+0)/2 , (2c+0)/2)
● E ( a+b, c)
●●●●●●●●●●●●●●●●●●●●●●●●
BD:
● B(2b,2c)
● D(2a,0)
● E ( (2a+2b)/2 , 2c/2)
● E ( a+b ,c)
●●●●●●●●●●●●●●●●●●●●●●●●●
So we conclude that the diagonals bisect each others in E.
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Answer:
43cm
Step-by-step explanation:
use the pythagorean theorem:
a² + b² = c²
25² + 35² = c²
625 + 1225 = c²
1850 = c²
√1850 = c
43 cm = c
your a, b and c values depend on where the values are on the triangle.
Answer:
The odds to get a blackjack (natural) as arrangement: 128 / 2652 = . 0483 = 4.83%. 4.83% is equivalent to about 1 in 21 blackjack hands.
Wow.... My brother Said that it took him a while to figure it out... but
add 110.25 and 55.45
you would get 165.70
multiply 165.70 by 4.5
then you would get 745.65
745.65 is your answer
Answer:
1. The correct answer is graph b
2. the correct answer is t>100
Step-by-step explanation:
Answer:
Here is a picture of how you will graph this equation
Step-by-step explanation:
Hope this Helped
