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igor_vitrenko [27]
3 years ago
7

The function FX = 1/x is not an example of a rational function. A. True B. False

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

false

Step-by-step explanation:

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a line with the slope of 1/3 passes through the points of (6,0). what is the equation in slope intercept form?​
sleet_krkn [62]

Answer:

y = 1/3x -2

Step-by-step explanation:

the equation for slope intercept form is y= mx + b.

m is the slope and b is where the line crosses the y-axis which is called the y-intercept.

to find the y-intercept plug in a coordinate on the line (6,0)

0 = 1/3(6) + b

then solve for b by first multiplying 1/3 by 6

0 = 2 + b

subtract 2 from both sides

-2 = b

and then you can plug b into the equation

y = 1/3x - 2

8 0
2 years ago
(8y²)(-3x²y²)(2/3xy⁴)<br><br> HELP PLEASEEEEEEEE
IRINA_888 [86]

Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

8y

2

×−3x

2

y

2

×

3

2

xy

4

2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

×

d

c

=

bd

ac

.

\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

2

×−3x

2

y

2

×2xy

4

3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

2

y

2

y

4

x

2

x

4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

y

2

y

4

x

2

x

5 Simplify -24\times 2−24×2 to -48−48.

\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

−48y

2

y

2

y

4

x

2

x

6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

−48y

2+2+4

x

2+1

7 Simplify 2+22+2 to 44.

\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

−48y

4+4

x

2+1

8 Simplify 4+44+4 to 88.

\frac{-48{y}^{8}{x}^{2+1}}{3}

3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

\frac{-48{y}^{8}{x}^{3}}{3}

3

−48y

8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

48y

8

x

3

11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

3

48y

8

x

3

to 16{y}^{8}{x}^{3}16y

8

x

3

.

-16{y}^{8}{x}^{3}

−16y

8

x

3

Done

6 0
2 years ago
HALP Can someone explain why this is a math question
erica [24]

Answer:

If the robot has more mass, then it will take a bigger force to lift up another object. If the robot is going to lift something up, it will use its arms, and its arms have mass, and the object has a mass as well. If the robot's arms have a mass of 10kg, and the object has a mass of 12kg, it will use a certain amount of force to lift up the object using it's arms. If the the robots arms were 5kg instead, it would take less force to lift of the same object using its arms.

4 0
3 years ago
I'm sorry but I have another one!
SIZIF [17.4K]
No mode or 43 i know the 43 sounds crazy but with math now days you never know.
8 0
3 years ago
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
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