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3 years ago

8

Carly is a catcher on the school softball team. By the end of the season, she had played 45% of the 49 games the team played. In

how many games did Carly not play?

1 answer:

Eduardwww [97]3 years ago

6 0

Carly did not play 22 games

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Find the value of x and the value of y.

kodGreya [7K]

Answer:

6√3 = x y =12

Step-by-step explanation:

Since the two sides of the triangles have equal angles then two sides have equal length

the sum of interior angles of triangles is 180° then the last angle is 60°

then the triangles have perfect sides of 12

y = 12

to calculate x

sin Ф = opposite/hypothenus

sin 60° = x/12

sin 60° = √3/2

( √3/2 ) x 12 = x

6√3 = x

3 0

3 years ago

Find the first four terms of the recursive sequence defined by the following formula: an = an-1 4 where a4 = 2 1 4 , , , 2 1 4.

Elina [12.6K]

The first four-term of the sequence is found by the given equation $a_{n-1} = 4a_n$ is given as 144, 36, 9, and 9/4.

<h3>What is a sequence?</h3>

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

The given equation will be

$\rm a_n = \dfrac{a_{n-1}}{4} \\\\a_{n-1} = 4a_n$

And

$a_4 = 2 \dfrac{1}{4} = \dfrac{9}{4}$

For n = 4, we have

$\rm a_{4-1} = 4a_4\\\\a_3 \ \ \ = 4*\dfrac{9}{4} \\\\ a_3 \ \ \ = 9$

For n = 3, we have

$\rm a_{3-1} = 4a_3\\\\a_2 \ \ \ = 4*9 \\\\ a_2 \ \ \ = 36$

For n = 2, we have

$\rm a_{2-1} = 4a_2\\\\a_1 \ \ \ = 4*36 \\\\ a_1 \ \ \ = 144$

More about the sequence link is given below.

brainly.com/question/21961097

7 0

2 years ago

Find the value of y of the figure below.

AURORKA [14]

I hope this helps you

4 0

3 years ago

Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl

Arlecino [84]

Answer:

A. 3.66 feet

Step-by-step explanation:

Using trigonometry, we know that ...

BC = DC·tan(30°)

AC = DC·tan(45°)

AB = AC -BC = DC(tan(45°) -tan(30°))

AB = 5√3·(1 -√3/3) = 5(√3 -1)

AB ≈ 3.66 . . . feet

8 0

3 years ago

A(-3,2) B(5,-4) midpoint is (1,-1)

lesya [120]

$CHECK:\\\\the\ midpoint\ AB:\left(\frac{-3+5}{2};\ \frac{2-4}{2}\right)=\left(\frac{2}{2};\ \frac{-2}{2}\right)=(1;-1)\\-------------------------------\\C(x;\ y)\\\\the\ midpoint\ AC:\left(\frac{-3+x}{2};\ \frac{2+y}{2}\right)\\\\B\ is\ the\ midpoint\ AC\ then:\\\\\frac{-3+x}{2}=5\ and\ \frac{2+y}{2}=-4\\\\-3+x=10\ and\ 2+y=-8\\\\x=10+3\ and\ y=-8-2\\\\x=13\ and\ y=-10\\\\Solution:C(13;-10).$

7 0

3 years ago