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3 years ago

What is the area of the trapezoid?

Mathematics

2 answers:

Elena L [17]3 years ago

7 0

Answer:

area of a trapezoid = 256 m²

Step-by-step explanation:

to find the area of the trapezoid

recall , the fomular for finding the area of a trapezoid

area of a trapezoid = ( a + b ) h/2

where a = 13m

b = 19m

height = 16m

area of a trapezoid= ( 13m + 19m) x 16m/2

area of a trapezoid = 32m x 8m

area of a trapezoid = 256 m²

therefore the area of the trapezoid is evaluated to be equals to 256m²

Rainbow [258]3 years ago

4 0

Answer:

256m²

Step-by-step explanation:

A=1/2{(b+b)×h}

A=1/2{(13+19)×16}

A=1/2(32×16)

A=1/2(512)

A=256

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The length, width, and height of the wooden box are 12.3 inches, 6.4 inches, and 7.5 inches respectively. The cost of painting t

PIT_PIT [208]

Answer:

$109.485

Step-by-step explanation:

4 0

3 years ago

What is the value of x in the equation 3x – 4y = 65, when y = 4? <br> the answer is x=27

Olenka [21]

What is the value of x in the equation 3x-4y=65 when y=4?

Simple...plug n chug..

3x-4(4)=65

3x-16=65

Now, isolate the variable, x....

3x-16=65
+16 +16

3x=81

Now, divide,

$\frac{3x}{3} = \frac{81}{3}$

x=27.

Thus, your answer.

7 0

3 years ago

Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten

serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

$\frac {dN}{dt}\propto -N$

$\Rightarrow \R\frac {dN}{dt}=-\lambda N$

$\Rightarrow \frac {dN}N=-\lambda dt$

Integrating both sides

$\Rightarrow \int \frac {dN}N=\int-\lambda dt$

$\Rightarrow ln|N|=-\lambda t+c$

When t=0, N= $N_0$ = initial amount

$ln|N_0|=-\lambda .0+c$

$\Rightarrow c=ln|N_0|$

$ln|N|=-\lambda t+ln|N_0|$

$\Rightarrow ln|N|-ln|N_0|=-\lambda t$

$\Rightarrow ln|\frac{N}{N_0}|=-\lambda t$

Decay equation:

$ln|\frac{N}{N_0}|=-\lambda t$

Given that, the half life of of element X is 11 minutes.

For half life, $N=\frac12 N_0$ , t= 11 min.

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11$

$\Rightarrow ln|\frac12}|=-\lambda . 11$

$\Rightarrow -\lambda . 11=ln|\frac12}|$

$\Rightarrow \lambda =\frac{ln|\frac12|}{-11}$

$\Rightarrow \lambda =\frac{ln|2|}{11}$ [ $ln|\frac12|=ln|1|-ln|2|=-ln|2|$ , since ln|1|=0]

N=154 grams, $N_0$ = 870 grams, t=?

$ln|\frac{N}{N_0}|=-\lambda t$

$\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t$

$\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}$

=27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0

3 years ago

Mr Lowry paid $32 for 5 boxes of crayons. How many dollars per box?

butalik [34]

Answer:

6 dollars and 40 cents

Step-by-step explanation:

To get the answer, you would do 32/5 which equals 6.4, which is the same as saying 6 dollars and 40 cents.

5 0

2 years ago

Please answer this! I'll classify you as brainliest, okay here it goes: what is x3+y3=z3. ( the3 is an exponent)

koban [17]

Answer:

Step-by-step explanation:

4 0

4 years ago