Answer:
(-5,1)
Step-by-step explanation:
Answer:
-3r + 15 ---> answer
Step-by-step explanation:
r < 5
You are going to multiply both sides with 3. The reason being is that 3 is a positive number and the equality sign will not change if you use +3.
3r < 15
Now, subtract 15 from both sides, you will get this:
3r < 15
-15 -15
-------------
3r — 15 < 0
Lastly, using the Modulus function, we are going to add a negative sign to the content of our previous step because it's already negative.
So, -3r + 15 is the final solution if r < 5 in the given equation of l3r-15l
1.) (2, 4) and (10, 8)
Distance: 4√5
Midpoint: (6, 6)
2.) (3, 8) and (7, 3)
Distance: √41
Midpoint: (5, 11/2)
3.) (4, 9) and (9, 5)
Distance: √41
Midpoint: (13/2, 7)
Answer:
D
Step-by-step explanation:
25 and 6
Coefficient is the number in front of the unknown variable
135
with math any absolute number cant be negative so you just make it positive
