Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Quadratic Formula:

<u>Algebra II</u>
Step-by-step explanation:
<u>Step 1: Define function</u>
f(x) = -x² - 6x - 14
<u>Step 2: Set up</u>
- Set equation equal to 0: -x² - 6x - 14 = 0
- Factor out -1: -(x² + 6x + 14) = 0
- Divide both sides by -1: x² + 6x + 14 = 0
<u>Step 3: Define variables</u>
a = 1
b = 6
c = 14
<u>Step 4: Find roots</u>
- Substitute:

- Exponents:

- Multiply:

- Subtract:

- Factor:

- Simplify:

- Factor:

- Divide:

So, we know both faucets open, can do the whole job in 6minutes
ok, how much has the faster cold water faucet done in 1minute then?
well, let's say the the rate of speed of the cold water faucet is "c", so in 1minute it has done 1/c of the whole work
now, we know the hot water faucet is slower, it takes it 3 times as long, that means is 1/3 the speed of the cold water faucet, so, how much does the hot water faucet do in 1min? well, we know is 1/3 fast as the cold one, the cold one is 1/c, what's 1/3 of 1/c? well, 1/3 * 1/c
now, we know they both added together, can do the whole job in 6 minutes, so in 1minute, they've done 1/6 of the job then
thus

25 degrees since all triangles add up to 180 56 and 99 together make 155 and subtract 180 by 155 and you get 25
1 and 1/2 is the same as 1.5 and 1.5 * 4 is 6 so I would say 4