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3 years ago

5. Solve log2x+ log12= 3. Round to the nearest hundredth if necessary. (1 point)

Mathematics

2 answers:

Serggg [28]3 years ago

5 0

Log 2x + log 12 = 3log 2x = 3 - log 12log 2x = 3 - 1.08log 2x = 1.922x = 10^1.922x = 83.33x = 83.33/2x = 41.67

nikitadnepr [17]3 years ago

4 0

1) log_8a-log_82

2) 2.089

3) 3.57 decibels

4) 0.82

5) 41.67

6) In x^2/c^5

7) 21,405 mowers

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a rectangle has a side length 2x+9 and side width x. If the perimeter is 36 cm, what is the value of x?

alukav5142 [94]

2(2x + 9) + 2(x) = 36

4x + 18 + 2x = 36

Combine like terms.

6x + 18 = 36

Subtract 18 from both sides.

6x = 18

Divide 6 on both sides.

x = 3

Hope this helps!

6 0

3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

4. Simplify - 4b +(-9k) – 6 – 3b + 12.

diamong [38]

Answer:

−7b−9k+6

Step-by-step explanation:

−4b+(−3b)=−7b

+(−9k)=−9k

12−6=6

6 0

3 years ago

Thank you so much for the answer in advance!

Aleonysh [2.5K]

A: 66 b:28 :))) have a good day

4 0

3 years ago

All other fields of science depend on a proper understanding of chemistry. true or false

Lina20 [59]

Absolutely ducking false no ways. Sound engineers don’t require it (more don’t use it) or computer scientists

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3 years ago