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lapo4ka [179]
4 years ago
9

The 25th percentile for waiting time in a doctor's office is 19 minutes. the 75th percentile is 31 minutes. the interquartile ra

nge is: 12 minutes. 16 minutes. 22 minutes. impossible to determine without knowing n.
Mathematics
1 answer:
Gennadij [26K]4 years ago
6 0
Wheres the rest of the question? 
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Malachy was thinking of a number. Malachy doubles it and gets an answer of 91.6. What was the original number?
zubka84 [21]

Answer:

45.8

Step-by-step explanation:

Say the number Malachy was thinking of is <em>x</em>.

Doubling it gives 2x, which we see also equals 91.6. Set these equal to each other:

2x = 91.6

To solve, we divide both sides by 2 and get x = 45.8, which is our answer.

5 0
3 years ago
Read 2 more answers
Refrer to the attached picture on which question is written. This question will be done according to Pathagoras theorem. This qu
Dvinal [7]

i got something different

3 0
3 years ago
What value in place of the question mark makes the polynomial below a perfect square trinomial x^2+24x+?
kykrilka [37]

Answer:

D

Step-by-step explanation:

Perfect square trinomials can be written as (a + b)² = a² + 2ab + b². In this case, we know that a = x so we can write this as x² + 2bx + b². Since we know that 2bx = 24x we can conclude that b = 12, so that means b² = 12 * 12 = 144.

7 0
3 years ago
Read 2 more answers
Please help and explain why you got it right please
gtnhenbr [62]

Answer:

y+7 = -3 ( x-4)

Step-by-step explanation:

First find two points on the graph to find the slope

( 1,2) and ( 3,-4)

The slope is given by

m = ( y2-y1)/(x2-x1)

m = ( -4-2)/(3-1)

    = -6/2

    =-3

We can use the point slope form

y - y1 = m(x-x1)  where m is the slope and x1,y1 is a point on the line

We have two choices with a slope of -3

We can either use and x coordinate of -2 or 4

for  -2, the y coordinate is not shown

for 4 , the y coordinate is -7

Using ( 4, -7) and m = -3

y--7 = -3( x- 4)

y+7 = -3 ( x-4)

4 0
3 years ago
Read 2 more answers
Simplify
OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}

and we can put all together

\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}

3 0
3 years ago
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