To Find Surface Area:
So Surface area is found according to this equation SA=2lw+2lh+2hw
6and 1/2 times 2 is 13 that would be the 2 sides
then you do 3 times 6 1/2 which is 19 1/2, which is the top and bottom
finally you do 3 times 9 1/5 which is 27 3/5.
Now since 1/2 and 1/5 are not the same, we find the LCM or Least Common Multiple, which is 10 so 1/2 is multiplied by 5 which is 5/10 and 3/5 is multiplied by 2 which makes 6/10.
Adding 5/10 and 6/10 is 11/10 or 1 1/10
13+6+9=28
28+1 1/10 = 29 1/10
and finally because we did surface area it is 29 1/10 CM^2
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To Find Volume:
The Equation used to find volume is l*w*h
The Length is 6 1/2
Height is 9 1/5
width is 3
First, lets again convert the fractions
5/10 and 6/10
6 5/10 times 9 6/10 is 62.4
62.4 times 3 is 187.2
The .2 and be put into 2/10 or 1/5 so the FINAL answer is 187 1/5
Another way to check this is
6*9*3=162
1/5*1/2
Hope this helped :)
~Ukiahsmith1
Answer:
g(x) 1/3-4
Step-by-step explanation:
In this case, we cannot simply take the average speed by
adding the two speeds and divide by two.
What we have to do is to calculate the time required
going to school and the return trip home.
We know that to calculate time, we use the formula:
t = d / v
where,
d = distance = 4.8 km = 4800 m
v = velocity
Let us say that the variables related to the trip going
to school is associated with 1, and the return trip home is 2. So,
t1 = 4800 m / (22.6 m / s)
t1 = 212.39 s
t2 = 4800 / (16.8 m / s)
t2 = 285.71 s
total time, t = t1 + t2
t = 498.1 s
Therefore the total average velocity is:
= (4800 m + 4800 m) / 498.1 s
= 19.27 m / s = 19.3 m / s
Answer:
19.3 m/s
Answer:
Option B is correct.
Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.
Step-by-step Explanation:
The clear, complete table For this question is presented in the attached image to this solution.
It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.
In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.
The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.
Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.
Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.
Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.
Hope this Helps!!!
