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3 years ago

H(x) = x2 j(x) = 2x2-5 find h(x) - j(x)

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

4 0

Answer:

Step-by-step explanation:

h(x) - j(x) => $x^2-(2x^2-5)$

The negative sign out in front of the set of parenthesis changes the signs of everything inside the parenthesis, so now we have, without parenthesis:

$x^2-2x^2+5$ which simplifies down to

$-x^2+5$

You might be interested in

Which matrix is equal to ( -6 -6.5 1.7 2 -8.5 19.3 )

DochEvi [55]

The matrix that is equal to the considered matrix [-6,-6.5,1.7; 2, -8..5, 19.3 ] is given by: Option D: [-6,-6.5,1.7; 2, -8..5, 19.3 ]

<h3>When are two matrices called being equal?</h3>

Two matrices are equal if and only if their shapes are same, and they've got the same elements for each corresponding row and column positions.

The missing options are specified in the image attached below.

The considered matrix is:

$\left[\begin{array}{ccc}-6&-6.5&1.7\\2&-8.5&19.3\end{array}\right]$

It has 2 rows and 3 columns.

Evaluating each of the options:

Option A and B are wrong as they've got 3 rows and 2 columns, which makes their shape not matching with the shape of the considered matrix.

Option C although has got 2 rows and 3 colums, but its elements are not matching with corresponding elements of the considered matrix.

Option D has 2 rows and 3 colums and its each element matches with the corresponding element of the considered matrix. (ie, for example, element common in first row and first column in option D is -6, and so as for the considered matrix, and similarly, all correspoding elements for each row and column is same in both matrices.)

Thus, the matrix that is equal to the considered matrix [-6,-6.5,1.7; 2, -8..5, 19.3 ] is given by: Option D: [-6,-6.5,1.7; 2, -8..5, 19.3 ]

Learn more about matrices here:

brainly.com/question/13430728

#SPJ1

4 0

2 years ago

What is the answer? I guessed a but I'm not sure.

Korolek [52]

$36\div9=2n\\
4=2n\\
n=2
$

4 0

4 years ago

What's the intuition behind the equation 1+2+3+⋯=−1121+2+3+⋯=−112 ?

Aleks [24]

The sum clearly diverges. This is indisputable. The point of the claim above, that

$1+2+3+\cdots=-\dfrac1{12}$

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.

The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it $C$ . Then

$\begin{matrix}C&=&1&+2&+3&+4&+5&+6&+\cdots\\4C&=&&+4&&+8&&+12&+\cdots\\-3C&=&1&-2&+3&-4&+5&-6&+\cdots\end{matrix}$

Now, recall the geometric power series

$\displaystyle\sum_{n\ge0}x^n=1+x+x^2+x^3+\cdots=\dfrac1{1-x}$

which holds for any $|x|$ . It has derivative

$\displaystyle\sum_{n\ge1}nx^{n-1}=1+2x+3x^2+4x^3+\cdots=\dfrac1{(1-x)^2}$

Taking $x=-1$ , we end up with

$1+2(-1)+3(-1)^2+4(-1)^3+\cdots=1-2+3-4+\cdots=\dfrac14$

and so

$-3C=\dfrac14\implies C=-\dfrac1{12}$

But as mentioned above, neither power series converges unless $|x|$ . What Ramanujan did was to consider the sum $1-2+3-4+\cdots$ as a limit of the power series evaluated at $x=-1$ :

$\displaystyle-3C=\lim_{x\to-1^+}\sum_{n\ge1}nx^{n-1}=\lim_{x\to-1^+}\frac1{(1-x)^2}=\frac14$

then arrived at the conclusion that $C=-\dfrac1{12}$ .

But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.

4 0

3 years ago

Can anyone please help me out with this?

nika2105 [10]

It works well to write the given angles on the diagram, then make use of the relationships for right angles and triangles.

8 0

3 years ago

Hamburgers cost $2 and hotdogs cost $2. The total cost of buying b hamburgers and d hotdoge can be expressed by C=3b+2d. how can

sveticcg [70]

C= 3b + 2d
Subtract 3b first.

C-3b = 2d
Divide by 2.

C-3b/2 = d

OR

C-3b
-------- = d Your final answer!
2

3 0

3 years ago