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Volgvan
3 years ago
12

Rounding or compatible 328+127=

Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

455

Step-by-step explanation:

                         328

                       <u>+ 127</u>

                         455

If this is not what you are looking for then please be more specific next time alright?

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You roll a blue number cube and a green number cube. Find the probability. P(blue 1 or 2 and green 1)
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Answer:

Step-by-step explanation:

1 for both

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For f(x)=2x+1 and g(x)=x^2-7, find (f+g)(x)
labwork [276]

For this case we have the following functions:

f (x) = 2x + 1\\g (x) = x ^ 2-7

We must find the following sum of functions:

(f + g) (x)

By definition we have to:

(f + g) (x) = f (x) + g (x)\\(f + g) (x) = 2x + 1 + x ^ 2-7\\(f + g) (x) = x ^ 2 + 2x-6

So, we have to:

(f + g) (x) = x ^ 2 + 2x-6

Answer:

(f + g) (x) = x ^ 2 + 2x-6

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4 years ago
Solve the equation 5x-6 is greater than 9
sweet [91]
5x-6><span>9
--------------------
Add 6 on each side of the equation
</span><span><span>5x-6</span>+6</span>><span>9+6
</span><span>5x</span>><span>15
</span>--------------------------
Divide each side by 5
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x > 3 is your answer
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Step-by-step explanation:

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3 years ago
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A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 42 states. What is the probability that sh
marissa [1.9K]

Answer:

P (She selects the route of four specific capitals) = \frac{1}{2686320}=(3.7226)10^{-7}

D. No,it is not practical to list all of the different possible routes because the number of possible permutations is very large.

Step-by-step explanation:

Let's start assuming that each route is equally likely to be chosen.

Assuming this, we can calculate P(A) where the event A is ''She selects the route of four specific capitals'' doing the following :

P(A) = Favourable cases in which the route of four specific capitals is selected / Total number of ways in 4 of 42 states

The favourable cases in which the route of four specific capitals is selected is equal to 1 .

For the denominator we need the permutation number of 4 in 42.

The permutation number is defined as :

nPr=\frac{n!}{(n-r)!}

42P4=\frac{42!}{(42-4)!}=\frac{42!}{38!}=2686320

The probability of event A is : \frac{1}{2686320}=(3.7226)10^{-7}

Finally for the other question : The option D is the correct because the number of possible permutations is 2686320 and is very large to be listed.

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3 years ago
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