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V125BC [204]
3 years ago
11

What is true about the sum of two polynomials?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

The sum is a binomial of degree 3.

Step-by-step explanation:

You are adding two binomials. Each binomial has two terms.

The terms 6s^2t and 4s^2t are like terms and combine to give the sum 10s^2t.

The terms -2st^2 and -3st^2 are like terms and combine to give the sum -5st^2.

The sum of the binomials is the binomial 10s^2t - 5st^2.

Since each original binomial is of degree 3, the sum is also of degree 3.

Answer: The sum is a binomial of degree 3.

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3 years ago
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

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Then, we have to subtract this number from x^2, so we have

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x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

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3 years ago
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irina1246 [14]

Operations that can be applied to a matrix in the process of Gauss Jordan elimination are :

replacing the row with twice that row

replacing a row with the sum of that row and another row

swapping rows

Step-by-step explanation:

Gauss-Jordan Elimination is a matrix based way used to solve linear equations or to find inverse of a matrix.

The elimentary row(or column) operations that can be used are:

1. Swap any two rows(or colums)

2. Add or subtract scalar multiple of one row(column) to another row(column)

as is done in replacing a row with sum of that row and another row.

3. Multiply any row (or column) entirely by a non zero scalar as is done in replacing the row with twice the row, here scalar used = 2

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