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TEA [102]
3 years ago
9

Multiply and simplify

xFormula1" title="( \sqrt{13}+3) ( \sqrt{13}-3 )" alt="( \sqrt{13}+3) ( \sqrt{13}-3 )" align="absmiddle" class="latex-formula">
Show steps please
Mathematics
2 answers:
Flura [38]3 years ago
8 0
(a+b)(a-b)= a^{2} - b^{2}  \\ ( \sqrt{13}+3 )( \sqrt{13}-3 )=   (\sqrt{13})^{2} - (3)^{2} =13-9=4
baherus [9]3 years ago
4 0
\sqrt{13}. \sqrt{13}+3. \sqrt{13}-3. \sqrt{13}-3.3=13-9=4
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Answer:

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Step-by-step explanation:

[] We can find our answer by plugging the x values into the functions as t and solving.

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[✓] f(x) = 2 * 4^{t}

(1, 8) }{}{}{ f(x) = 2 * 4^{1} = 2 * 4 = 8

(2, 32) }{}{}{ f(x) = 2 * 4^{2} = 2 * 16 = 32

(3, 128) }{}{}{ f(x) = 2 * 4^{3} = 2 * 64 = 128

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[✗] f(x) =  4^{t}

(1, 8) }{}{}{ f(x) = 4^{1}  = 4 ≠ 8

-> This function does not model the data as it does not fulfil the first point

[✗]  f(x) = 4 * 2^{t}

(1, 8) }{}{}{ f(x) =  4 * 2^{1} = 4 * 2 = 8

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-> This function only models (1, 8) but does not fully model the data

[✗] f(x) =  8^{t}

(1, 8) }{}{}{ f(x) =  8^{1} = 8

(2, 32) }{}{}{ f(x) =    8^{2} = 64 ≠ 32

-> This function only models (1, 8) but does not fully model the data

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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3 years ago
https://lh5.googleusercontent.com/IDO6WqjkvxWIGc9p2e16rebEccq4cDRqA5qfNh3vnrby_VHQIAfCDUJ_xR4MGwzJYlcbifs1fua-bWQ9GnlGL9f7WeIw1H
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this link doesn't work. what is the question?

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