7/10s of 40 would be 28 so that leave 12 hours to work inside
Answer:
0.00665
0.006951
Step-by-step explanation:
If the first child is born with the affliction, there's a 0.05 probability that the second child will be born with the affliction. Which means there's a 0.95 probability that they won't.
The probability that the first child is born with the affliction but not the second is therefore:
P = 0.007 × 0.95
P = 0.00665
There's a 0.007 probability that the first child will be born with the affliction, which means there's a 0.993 probability that they won't. If the first child isn't born with the affliction, then the probability the second child will have it is 0.007.
So the probability that the first child is not born with the affliction and the second child is would be:
P = 0.993 × 0.007
P = 0.006951
Answer:
Distributive property
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