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liberstina [14]
3 years ago
11

Please help!! Question is in the picture!!

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0

\frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

<u>Experimental probabilities from the table:</u>

Probability of getting 1 = \frac{12}{60}=\frac{1}{5}

Probability of getting 2 = \frac{17}{60}

Probability of getting 3 = \frac{15}{60}=\frac{1}{4}

Probability of getting 4 = \frac{16}{60}=\frac{4}{15}

<u>To determine which are the experimental probabilities from the table:</u>

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: \frac{17}{60}

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: \frac{1}{4}

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: \frac{7}{15}

This is not obtained above. So, it is not the experimental probability.

Option E: \frac{12}{43}

This is not obtained above. So, it is not the experimental probability.

Hence \frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

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Answer:

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Formatting the question gives;

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(iv) Take the square root of both sides

v = √ [(m²g - ma) / k]            --------------(ii)

From the question:

a = 2.8

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Substitute these values into equation (i) as follows;

v = √ [(12²(9.8) - 12(2.8)) / (8/3)]

v = √ [(1411.2 - 33.6) / (8/3)]

v = √ [1377.6 / (8/3)]

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v = 22.73

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