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Ymorist [56]
3 years ago
9

Sam is determining the area of a triangle. In this triangle, the value for the height is a terminating decimal, and the value fo

r the
base is a repeating decimal. What can be concluded about the area of this triangle?
Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

Answer:

The area is rational because the numbers in the formula are rational.

Step-by-step explanation:

All repeating decimals are still rational because they can be expressed as fractions. For example,

$\frac{1}{7}=0.\overline{142857}$\end{document}

So every recurring decimal must be a fraction.

Also every terminating decimal can be represented as a fraction.

0.25  =  \frac{1}{4}

So  the area is rational because the numbers are rational.

Area = \frac{1}{2} X Base X Height

Base is Rational and Height is Rational. Hence Area=Rational.

When these rational numbers are substituted into the formula,the area must be rational.

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pantera1 [17]

Answer:

M=a2-a1/b2-b1

Step-by-step explanation:

-3-a/-2-1

-4a/3

/-4/-4

a=3/-4

7 0
2 years ago
Write perimeter and area of circle​
alexira [117]

Answer:

The perimeter of a circle is π × d. Here's is the diameter of the circle. Hence, the perimeter of a circle is half of that of the circle that is ½ π × d.

The area of a circle is pi times the radius squared (A = π r²). Learn how to use this formula to find the area of a circle when given the diameter.

Step-by-step explanation:

8 0
4 years ago
The sum of 5x and 2x is at least 14
tatuchka [14]

5x+2x>= 14

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6 0
4 years ago
Read 2 more answers
Jim's father bought a new car 3 years ago for
Alexus [3.1K]

30% of 50,400 = 30240.

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4 0
3 years ago
Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5​
Bond [772]

Answer:

The solution to the equation system given is:

  • <u>x = 2</u>
  • <u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

  1. 2x + 3y = 1
  2. 3x + y = 5​

Following Crammer's Rule, we have the matrix form:

\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Now we solve using the determinants:

x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2

y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

  • 2x + 3y = 1
  • 2(2) + 3(-1)= 1
  • 4 - 3 = 1
  • 1 = 1

And, with the second equation:

  • 3x + y = 5​
  • 3(2) + (-1) = 5
  • 6 - 1 = 5
  • 5 = 5

 

4 0
3 years ago
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