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Leya [2.2K]
3 years ago
5

Sabian que hay una violadora sexuar el nombre de usario es SASHENKAFASION me acaba de decir que hackio en donde vivo,mi nombre c

ompleto y nombre de mis familiares tengan cuidado
Computers and Technology
1 answer:
grin007 [14]3 years ago
4 0
Gracias por avisar eres muy amable
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Protocol 2 - Check for Errors
Lapatulllka [165]

Please note that the Problem to be solved from Protocol 1 is not provided hence the general answers. To construct and send, open a network environment a single multi-packet message, simply click "Add Packet" and then click "Send at Once".

<h3>How will the receiver know the order of the packets or if any are missing?</h3>

If the text or message sent does not make any reading sense, or if certain words are jumbled and out of place, then it is clear that something is wrong.

If the messages arrive in a coherent fashion, then the packet was fully received.

<h3>How will the receiver request missed packets and what will the sender do in response?</h3>

Where the users are familiar with the Transmission Control Protocol, lost packets can be detected when there is a timeout. Lost packets are referred to as Dropped packets.

Learn more about Packets at:
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7 0
1 year ago
Which of these field types allows multiple, non-exclusive options?
AlexFokin [52]

Question:

Which of these field types allows multiple, non-exclusive options?

A. multi-part

B. checkbox

C. text

D. radio button

E. button

Answer:

The correct option is B) Checkboxes

Explanation:

Field types is a terminology often associated with Database Management.

A field type is often found in a data collection apparatus such a form. It's inherent quality or nature will determine the kind of data that it can collect.

Some field types allow for exclusive options. That is, in some data field types, it's impossible to select more than one option.

For example, a Button field type can only collect one type of value.

A Checkbox on the other can be configured to allow for multiple selections which may or may not be exclusive.

When working with Microsoft Access, for instance, you are required to select the name of the <em>field </em>and define the type of <em>field data.</em>

<em />

Cheers!

6 0
3 years ago
What are characteristics of fluent readers? Check all that apply. reading known words automatically pronouncing words correctly
IRINA_888 [86]

Answer:

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Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th
ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0
3 years ago
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