The lengths of the line segments are summarized in the following list:
- DF = 3
- DE = 8 / 3
- FG = 3
- FH = 9 / 2
- GH = 3 / 2
- EH = - 11 / 6
<h3>How to calculate the length of a line segment based on point set on a number line</h3>
Herein we have a number line with five points whose locations are known. The length of each line segment is equal to the arithmetical difference of the coordinates of the rightmost point and the leftmost point:
DF = - 1 - (- 4)
DF = 3
DE = (- 1 - 1 / 3) - (- 4)
DE = 3 - 1 / 3
DE = 8 / 3
FG = 2 - (- 1)
FG = 3
FH = (3 + 1 / 2) - (- 1)
FH = 4 + 1 / 2
FH = 9 / 2
GH = (3 + 1 / 2) - 2
GH = 1 + 1 / 2
GH = 3 / 2
EH = (3 + 1 / 2) + (- 1 - 1 / 3)
EH = - 2 + (1 / 2 - 1 / 3)
EH = - 2 + 1 / 6
EH = - 11 / 6
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Answer:
Step-by-step explanation:
Therefore 
Answer:
21022.
Step-by-step explanation:
Find the prime factors of 10508:
2 ) 10508
2 ) 5254
37 ) 2627
71.
50208 = 2*2*37*71.
Now there is no integer value for a that would fit (a+ 1)(a - 5) = 10508 .
But we could try multiplying the LCM by 2:-
= 21016 = 2*2*2*37*71.
= 2*2*37 multiplied by 2 * 71
= 148 * 142.
That looks promising!!
a - 5 = 142 and
a + 1 = 148
This gives 2a - 4 = 290
2a = 294
a = 147.
So substituting a = 147 into a^2 - 4a + 1 we get:
= 21022.
Answer:
yes
Step-by-step explanation:
there is a single x value for every y value
