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Lerok [7]
3 years ago
8

PLEASE ANSWER ASAP (10 POINTS)

Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

Answer:

(x+5)(x+7)

Step-by-step explanation:

Let's factor x2+12x+35

x2+12x+35

The middle number is 12 and the last number is 35.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get 12

Multiply together to get 35

Can you think of the two numbers?

Try 5 and 7:

5+7 = 12

5*7 = 35

Fill in the blanks in

(x+_)(x+_)

with 5 and 7 to get...

(x+5)(x+7)

Answer:

(x+5)(x+7)

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A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of m
posledela

Answer:

Check the attached document for the solutions, cheers

Step-by-step explanation:

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7 0
3 years ago
Solve the equation for x.<br><br><br> x2 = 576<br> /\<br> || <br> is supposed to be 2 over x
aleksklad [387]

Answer:

288

Step-by-step explanation:

2/x = 576

you have to make the x by itself so you would have to multiply 1/2 to 2/x for the first part

then you would carry the 1/2 over to 576 and multiply that by 1/2

the answer would become x = 288

5 0
3 years ago
Read 2 more answers
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navik [9.2K]

107 in the verse of 180 the whole turn will evaluate to 73.

Step-by-step explanation:

5 0
3 years ago
What is the outlier of 29, 2, 28, 30, 26, 31
Vladimir [108]

Answer:

2

Step-by-step explanation:

Given the data : 29, 2, 28, 30, 26, 31

Outlier ;

Lower :Q1 - (1.5 * IQR)

Upper : Q3 + (1.5 * IQR)

Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range

Using calculator :

Q1 = 26

Q3 = 30

IQR = (Q3 - Q1) = 30 - 26 = 4

Lower : 26 - (1.5 * 4) = 20

Upper : 30 + (1.5 * 4) = 36

Hence, the number in the given data which falls outside the range is 2

4 0
3 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
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