Answer is –4/5
Rearrange the equation to make y the subject
5y = –4x – 35
y = –4/5 x – 7
If the line is parallel to the other line, they both have the same gradients but different y-intercepts, so the gradient is just as is.
Answer:
12m^2 - 9m -30
Step-by-step explanation:
So rewrite the equation to this:
4m * 3m
4m * -6
5 * 3m
5 * -6
Now solve:
4m * 3m = 12m^2
4m * -6 = -24m
5 * 3m = 15m
5 * -6 = -30
Now add them together in order:
12m^2 - 24m + 15m - 30
Simplify -24m and 15m:
12m^2 - 9m -30
Thus
12m^2 - 9m -30 is the answer
Hope this helps!
Answer:
La respuesta esta abajo
Step-by-step explanation:
La pregunta no está completa porque no contiene gráficos, pero te mostraré cómo responderla.
La ecuación de un gráfico de línea recta viene dada por:
y = mx + b; donde y y x son variables, m es la pendiente de la gráfica y b es la intersección en y (que es el valor de y cuando x es 0)
Dado que la ecuación de la gráfica es y = mx, comparando con la ecuación de una línea recta (y = mx + b), podemos concluir que la gráfica con una ecuación y = mx, tiene una pendiente de my una intersección con y de 0.
Esto significa que la gráfica pasa por el origen sin tocar el eje y. Además, la gráfica tiene una pendiente positiva.
Answer: Ox=3,y=11 Ox
Step-by-step explanation:
Answer:
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
7)
now decide which parts we know and what we want to slove for and pick the function that has those in it
we also know that small angle down at the point b/c we can use that the inside of trianle angles add to 180
180 = 75 + 90 + X
15° = X
where x is the angle at that sharp point on the triangle
I want to use that 15° angle in one of the above formulas as it's Opposite of that side we want to know, and also adjcent to that side we know , so i'll pick TOA since it's got all of those in it. Opp = x for this triangle
Tan(15) = Opp / 15
15* Tan(15) = Opp
4.0192 = Opp
so that's x
x = 4.0162 units , what ever they are
8)
the angle is 43° and we know the adjacent side and we want the Hypotenuse , now i'll pic CAH since it's got those pieces in it
Cos(43)= 31 / Hyp
some algebra just to switch Hyp out of the denominator
Hyp = 31 / Cos(43)
some tapping on my calculator
Hyp = 41.714
That's x for the second triangle
x = 41.71 units , what ever they are
:)
