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cupoosta [38]
3 years ago
13

Eight less than four times a number is less than 56. What are the possible values of that number?

Mathematics
2 answers:
jasenka [17]3 years ago
5 0

Answer:

A.  x > 12

Step-by-step explanation:

Eight less than four times a number is less than 56. What are the possible values of that number?

x less-than 12

x greater-than 12

x less-than 16

x greater-than 16

Damm [24]3 years ago
4 0

For this case we can algebraically rewrite the expression given as:

8-4x

Where:

x: Represents the unknown number

Subtracting 8 from both sides of the inequality we have:

-4x

Dividing between 4 on both sides of the inequality:

-x

We multiply by -1 on both sides taking into account that the sense of inequality changes:

x> -12

ANswer:

x> -12

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Find f(5). f(x) = x2 + 2x A)15 B)20 C)30 D)35
inysia [295]

f(5) means to replace x in the equation with 5 then solve.

f(x) = x^2 +2x

f(5) = 5^2 + 2(5)

f(5) = 25 +10

f(5) = 35

The answer is D)35

7 0
3 years ago
Can someone with knowledge see what I did wrong on number 4<br>also see if number 3 is right​
Yakvenalex [24]

Answer:

#4.  m=0;

#3.  m = \frac{-1}{2}

Step-by-step explanation:

It seems right.

#4.  

Maybe your teacher wants you to write m=0; because when a fraction has a numerator equal to zero then the fraction is zero.

#3.

Maybe your teachers want you to simplify the fraction and write m = \frac{-1}{2}

7 0
3 years ago
Read 2 more answers
Suppose that a is a one-dimensional array of ints with a length of at least 2. Which of the following code fragments successfull
elixir [45]

Answer:

E)II and III only

Step-by-step explanation:

This can be seen with examples. Say a[0]=1 and and a[1]=2.

for I , the first line of code would be:

a[0]=a[1];

thus, we would get a new value for a[0]=2.

The second line of code

a[1]=a[0]; uses the new value of a[0], so we would get a[1]=2.

The end result is a[0]=2, and a[1]=2 which doesn't exchange the values of the first two elements.

For II the first line of code

int t= a[0]; saves the original value of a[0] to t, so we get t=1.

the second line of code

a[0]=a[1]; changes the value of a[0]  to that of a[1]. Thus, in our example a[0]=2.

the final line

a[1]=t; changes the value of a[1] to the original value of a[0], giving us a[1]=1 and a[0]=2, what we were looking for.

For III

the first line of code

a[0]=a[0]-a[1];

gives us

a[0]=1-2

the secon line

a[1]=a[1]+a[0];

takes the new value of a[0] and replaces it in the expression

a[1]= 2+(1-2)=1

the last line

a[0]=a[1]-a[0];

takes the new value of a[0] and a[1] and replaces the in the expression

a[0]=1-(1-2)=1-1+2=2

which exchanges the values needed.

So we can see that only II and III do what we require, giving us E as the answer.

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Answer: write a triangle and a quad.

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