(0,8) on the y axis and (8,0) on the x axis.
Hope this helps if so feel free to give me a brainliest!!!
Have a wonderful day :)
Answer:
336
Step-by-step explanation:
8P3
=8!(8-3)!
=8!5!
=8x7x6
=336
Answer: The answer is (D) ![24x+2.](https://tex.z-dn.net/?f=24x%2B2.)
Step-by-step explanation: Given that there is a rectangle, where length of the rectangle is given by
![\ell=4x+5,](https://tex.z-dn.net/?f=%5Cell%3D4x%2B5%2C)
and width of the rectangle is given by
![b=8x-4.](https://tex.z-dn.net/?f=b%3D8x-4.)
We are to find the perimeter of the rectangle. To do so, we need to add two times length with two times breadth of the rectangle.
Therefore, perimeter is given by
![p=2\ell+2b=2\times(4x+5)+2\times(8x-1)=8x+10+16x-8=24x+2.](https://tex.z-dn.net/?f=p%3D2%5Cell%2B2b%3D2%5Ctimes%284x%2B5%29%2B2%5Ctimes%288x-1%29%3D8x%2B10%2B16x-8%3D24x%2B2.)
Thus, the correct option is (D).
Answer:
184 in.^2
Step-by-step explanation:
The cross section through the center of a sphere is a circle whose radius is equal to the radius of the sphere.
area of circle
![A_{circle} = \pi r^2](https://tex.z-dn.net/?f=A_%7Bcircle%7D%20%3D%20%5Cpi%20r%5E2)
![\pi r^2 = 46](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E2%20%3D%2046%20)
![r^2 = \dfrac{46}{\pi}](https://tex.z-dn.net/?f=%20r%5E2%20%3D%20%5Cdfrac%7B46%7D%7B%5Cpi%7D%20)
![r = \sqrt{\dfrac{46}{\pi}}](https://tex.z-dn.net/?f=%20r%20%3D%20%5Csqrt%7B%5Cdfrac%7B46%7D%7B%5Cpi%7D%7D%20)
![r = 3.83 ~in.](https://tex.z-dn.net/?f=%20r%20%3D%203.83%20~in.)
surface area of sphere
![SA = 4 \pi r^2](https://tex.z-dn.net/?f=%20SA%20%3D%204%20%5Cpi%20r%5E2%20)
![SA = 4 \times \pi \times (3.83)^2](https://tex.z-dn.net/?f=%20SA%20%3D%204%20%5Ctimes%20%5Cpi%20%5Ctimes%20%283.83%29%5E2%20)
![SA = 184~in.^2](https://tex.z-dn.net/?f=%20SA%20%3D%20184~in.%5E2%20)
Answer:
That would be 2/7
Step-by-step explanation:
Using substitution. x^2 +x+1 at 1 is 7
sqrt4 is 2
2/7