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cricket20 [7]
3 years ago
12

Is the height of a basketball hoop negative value, positive value, or latitude at the equator.

Mathematics
1 answer:
erastova [34]3 years ago
6 0
 it would have to be positive value
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What is (-7) x (-3) in multiplying integers
Roman55 [17]

<h2>(-7) x (-3) =<u> 21</u></h2>

.... Hope this will help....

6 0
3 years ago
Read 2 more answers
HELP ! MARKING BRAINLEST TO WORK THIS OUT
natulia [17]

Answer:

16% = 73.6

Step-by-step explanation:

If 1% is = 4.6 then 16% is

1* 16 % = 4.6 * 16

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Find the solution of the differential equation that satisfies the given initial condition. dy/dx=x/y , y(0)=-1
Charra [1.4K]

Separating variables, we have

\dfrac{dy}{dx} = \dfrac xy \implies y\,dy = x\,dx

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\dfrac12 y^2 = \dfrac12 x^2 + C

Given that y(0)=-1, we find

\dfrac12 (-1)^2 = \dfrac12 0^2 + C \implies C = \dfrac12

Then the particular solution is

\dfrac12 y^2 = \dfrac12 x^2 + \dfrac12

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y = \pm\sqrt{x^2 + 1}

and because y(0)=-1, we take the negative solution to accommodate this initial value.

\boxed{y(x) = -\sqrt{x^2+1}}

7 0
2 years ago
A rectangular park of length 60 m breadth 50 m encloses w volleyball court of length 18 m and breadth 10 m. Find the area of the
Zanzabum

Given

A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.

To find:

The area of the park excluding the court at the rate of Rs 110 per square meter.​

Solution:

Area of a rectangle is:

Area=length \times breadth

Area of whole park is:

A_1=60 \times 50

A_1=3000

Area of volleyball court is:

A_2=18 \times 10

A_2=180

Now, the area of the park excluding the court is:

A=A_1-A_2

A=3000-180

A=2820

Therefore, the area of the park excluding the court is 2820 square meter.

4 0
3 years ago
What's sixty nine thousand one hundred eight written in standred form
Vadim26 [7]
The answer is 69,108
3 0
3 years ago
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