Answer:
<h2>
The eleventh term of the sequence is 64</h2>
Step-by-step explanation:
The sequence given is an arithmetic sequence
14, 19, 24, …………., 264
The nth term of an arithmetic sequence is given as;
Tn = a+(n-1)d where;
a is the first term = 14
d is the common difference = 19-14=24-19 = 5
n is the number of terms = 11(since we are to look for the eleventh term of the sequence)
substituting the given values in the formula given;
T11 = 14+(11-1)*5
T11 = 14+10(5)
T11 = 14+50
T11 = 64
The eleventh term of the sequence is 64
Center: 0,0
vertex: 5,0
vertex2 (-5,0)
Answer:
Step-by-step explanation:
First use distributive property: a(b + c) = a*b + a*c
3n - 6 = -8(6 + 5n)
3n - 6 = 6 * (-8) + 5n *(-8)
3n - 6 = -48 - 40n
Now add 40n to both sides
3n - 6 + 40n = -48 - 40n + 40n
43n - 6 = -48
Now add 6 to both sides
43n - 6 + 6 = -48 + 6
43n = -42
n = -42 /43
Answer:
16 and 40
Step-by-step explanation:
Greater than 8,
The highest common factor is 8, the lowest common multiple is 80.
So, the two numbers are greater than 8, divisible by 8 ( highest common factor.)
The two numbers are 16 and 40.
Hope this helps plz mark brainliest :D
The answer is B.) x2-14x+2y
