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m_a_m_a [10]
3 years ago
12

What’s 78.5 rounded to the nearest tenth?

Mathematics
1 answer:
siniylev [52]3 years ago
4 0
It already rounded to the nearest tenth
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Shannon is planning to tile a rectangular kitchen countertop that is 24 inches wide and 64 inches long. She determined that 1 ti
kow [346]

Answer:

96

Step-by-step explanation:

\frac{24*64}{4*4}=96\\

or

\frac{24}{4}=6, \frac{64}{4}=16\\6*16=96

7 0
3 years ago
Below are tabulated a number of Rockwell G hardness values that were measured on a single steel specimen. Compute
Mashcka [7]

Answer:

a) 48.408

b) 1.235

Step-by-step explanation:

a)

The average hardness value xbar can be computed as

xbar=sum of values/number of values

xbar=(46.5+46.9+49.4+50.3+49.8+48.8+47+47.7+48.3+49.4+47.8+49)/12

xbar=580.9/12

xbar=48.408 (rounded to 3 decimal places).

The average hardness value is 48.408.

b)

The standard deviation hardness value s can be computed as

s=\sqrt{\frac{sum(x-xbar)^2}{n-1} }

x              x-xbar  (x-xbar) ²

46.5  -1.90833 3.64174

46.9  -1.50833 2.27507

49.4    0.99167 0.98340

50.3     1.89167 3.57840

49.8     1.39167 1.93674

48.8    0.39167 0.15340

47.0           -1.40833 1.98340

47.7   -0.70833 0.50174

48.3           -0.10833 0.01174

49.4    0.99167  0.98340

47.8           -0.60833 0.37007

49.0    0.59167 0.35007

Total                               16.7692

s=\sqrt{\frac{16.7692}{12-1} }

s=\sqrt{\frac{16.7692}{11} }

s=\sqrt{1.5245}

s=1.2347

s=1.235 (rounded to 3 decimal places)

The standard deviation hardness value is 1.235.

4 0
4 years ago
Solve : <br>4² ( 4³ )<br>with work shown ​
stepan [7]

Answer:

1024

Step-by-step explanation:

4²(4³)

4×4(4×4×4)

16(16×4)

16(64)

16×64

=1024

7 0
3 years ago
What is the area of this figure? Use 3.14 for pi.
andrey2020 [161]

Answer:

24,53cm²

Step-by-step explanation:

rectangle area=length×width=7×3

=21cm²

circle area=1/2Π r²

=1/2×3.14×1.5×1.5

=3.5325cm²

add the two areas

21+3.53=24,53cm²

6 0
3 years ago
What is the measure of 2?
Fiesta28 [93]

Answer:

Value of x:

{ \tt{(7x + 1) \degree + (18x + 4) \degree = 180 \degree}} \\  { \tt{25x + 5 = 180}} \\ { \tt{25x = 175}} \\ x = 7

Finding m‹2 :

{ \tt{m \angle2 = (7x + 1) \degree}} \\ { \tt{m \angle2 = (7 \times 7) + 1}} \\ { \bf{m \angle2 = 50 \degree}}

8 0
3 years ago
Read 2 more answers
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