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Bad White [126]
4 years ago
9

What is 3a*3a*3a*3a ? It says write it in exponential form but I'm having trouble trying to do that .

Mathematics
1 answer:
konstantin123 [22]4 years ago
3 0
3a*3a*3a*3a=6a^2 *6a^2 =36a^4
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What are the coordinates of the point?
Olenka [21]

Answer:

(-3,6)

Step-by-step explanation:

As  graph shows x=-3 and y=6  

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9(1 + w) – 5w = 5<br> W=
RoseWind [281]

Answer:

w= -1

Step-by-step explanation:

Use PEMDAS to solve.

9(1 + w) - 5w = 5

distribute 9 to everything inside the parentheses.

9 x 1 = 9

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rewrite equation

9 + 9w - 5w = 5

combine like terms

9w - 5w = 4w

rewrite equation

9 + 4w = 5

subtract 9 from both sides

9 - 9 = 0

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3 years ago
What are the two equations that need to be solved to find the solutions for the absolute value equation |3x+5|=x-1
Eduardwww [97]

the 2 equations that need to be solved are [3x+5] and x-1. If you need the answer to what x is you'd solve it by evening out the problems. so first add one to both so you'd have 3x+6=x then you'd take the 3x and subtract it from both sides making it 6=-2x. Then divide 6 by negative 2 making it -3=x.

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The equation of a circle is x2+y2−12x+6y+20=0 .
Rufina [12.5K]

Answer:

The radius is r=5 units

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

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we have

x^{2}+y^{2}-12x+6y+20=0

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}-12x)+(y^{2}+6y)=-20

Complete the square twice. Remember to balance the equation by adding the same constants to each side

(x^{2}-12x+36)+(y^{2}+6y+9)=-20+36+9

(x^{2}-12x+36)+(y^{2}+6y+9)=25

Rewrite as perfect squares

(x-6)^{2}+(y+3)^{2}=5^{2}

therefore

The center is the point (6,-3) and the radius is r=5 units

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