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2 years ago

Hi! I have a geometry question below, could someone please take a look?

Mathematics

1 answer:

AnnyKZ [126]2 years ago

7 0

Answer:

109 degrees.

Step-by-step explanation:

m< AEB = 1/2 (98 + 120)

= 1/2 * 218

= 109 degrees.

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Steve and Elizabeth decide to become partners in a children’s cooking school. They need $80,000 for the franchise. They invest i

PilotLPTM [1.2K]

Answer:

The share of Steve is $34,285 .71

The share of Elizabeth is $45,714.28

Step-by-step explanation:

The total investment of Steve and Elizabeth in cooking school = $80, 000

The ratio of investment of Steve and Elizabeth = 3: 4

Let us assume the common factor in the ratio is m.

So, the ratio of Steve = 3 m

and the ratio of Steve = 4 m

So, according to the question:

⇒ 3 m + 4 m = 80,000

or, 7 m = 80,000

⇒ m = 80,000 / 7 = 11,428.57

or, m = 11,428.57

⇒ The share of Steve = 3 m = 3 x (11,428.57) = 34,285 .71

⇒ The share of Elizabeth = 4 m = 4 x (11,428.57) = 45,714.28

4 0

2 years ago

Solve for x<br> -4+4x=16

vesna_86 [32]

X=5 because 4x5=20 and 20-4=16

7 0

2 years ago

Read 2 more answers

I WILL DO ANYTHING YOU NAME IT BUT PLz SOLVE THIS

vekshin1

Answer: AD = 9cm

Step-by-step explanation: This is a 30-60-90 triangle, so the hypotenuse is equal to twice the length of the short side of the right angle.

BC is the short side of the large triangle, so AB, the hypotenuse of the large triangle is 2×6, 12 cm

BC is also the hypotenuse of the small triangle, ΔBCD, so it is twice the length of BD, to that makes BD = 6/2= 3

Subtract BD from AB.

That's 12 - 3 = 9 the length of AD

6 0

2 years ago

If p→q is true and p is true, then we know q is true.<br><br> True<br> False

slega [8]

Answer:

false

Step-by-step explanation:

6 0

3 years ago

1. Parallelogram ABCD is similar to

ss7ja [257]

Answer:

The length of GH is 2 inches

Step-by-step explanation:

The given parameters are;

Parallelogram ABCD ~ Parallelogram EFGH

Segment BC of parallelogram ABCD corresponds to segment FG of parallelogram EFGH

Similarly

Segment CD of parallelogram ABCD corresponds to segment GH of parallelogram EFGH

In parallelogram ABCD, we have;

Segment BC = 21 in.

Segment CD = 6 in.

In parallelogram ABCD, we have;

Segment FG = 7 in.

Given that parallelogram ABCD is similar to parallelogram EFGH, we have;

$\dfrac{\overline{BC}}{\overline{FG}} = \dfrac{\overline{CD}}{\overline{GH}}$

Which by substitution, gives;

$\dfrac{21}{7} = 3 = \dfrac{6}{\overline{GH}}$

$\therefore \overline{GH} = \dfrac{6}{3} = 2$

$\overline{GH}$ = 2 inches

8 0

2 years ago