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Paul [167]
4 years ago
15

Question 16 need help thank you

Mathematics
1 answer:
Mariulka [41]4 years ago
5 0
You need to find the surface area of the rectangular prism and the triangular prism and add them up to find the answer.

Rectangular prism:
SA=2(lw+wh+lh)
SA=2(437.5+406.25+1137.5)
SA=2(1981.25)
SA=3962.5 sq cm

Triangular prism:
SA=2(1/2bh)+3(slanted height)*w
SA=2(235.75)+3(293.75)
SA=471.5+881.75
SA=1352.75 sq cm

3962.5+1352.75=5315.25 sq cm

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8 0
3 years ago
Round off to the underlined place values. 1 0.5242 2. 2.1616 3. 5.4852 4. 0.5862 5. 5.9658 6. 2.8959 7. 8.2584 8. 8.8956 9. 4.14
sladkih [1.3K]

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6 0
3 years ago
Help help help help pls​
Ronch [10]

Answer:

[24, 375]

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6 0
3 years ago
Help please, i don't understand it!!!!
velikii [3]
V=\dfrac{4}{3}\pi r^3\ \ \ |\cdot\dfrac{3}{4}\\\\\pi r^3=\dfrac{3V}{4}\ \ \ \ |:\pi\\\\r^3=\dfrac{3V}{4\pi}\ \ \ |:r\\\\r^2=\dfrac{3V}{4\pi r^2}

Substitute to S.A.

S.A.=4\pi r^2=4\pi\cdot\dfrac{3V}{4\pi r^2}=\dfrac{3V}{r}

\dfrac{S.A.}{V}=\dfrac{4\pi r^2}{\frac{4}{3}\pi r^3}=\dfrac{3}{r}

\dfrac{S.A.}{V}=1\to\dfrac{3}{r}=1\to r=3

Answer: B
6 0
3 years ago
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