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Paul [167]
4 years ago
15

Question 16 need help thank you

Mathematics
1 answer:
Mariulka [41]4 years ago
5 0
You need to find the surface area of the rectangular prism and the triangular prism and add them up to find the answer.

Rectangular prism:
SA=2(lw+wh+lh)
SA=2(437.5+406.25+1137.5)
SA=2(1981.25)
SA=3962.5 sq cm

Triangular prism:
SA=2(1/2bh)+3(slanted height)*w
SA=2(235.75)+3(293.75)
SA=471.5+881.75
SA=1352.75 sq cm

3962.5+1352.75=5315.25 sq cm

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Last Sunday the average temperature was 8% higher than the average temperature Sundays ago. The average temperature two Sundays
Fofino [41]

Answer:

1.08.

Step-by-step explanation:

4 0
3 years ago
75% of the children at Fisher Elementary walk to school. If there are 200 students at Fisher Elementary, how many walk to school
BlackZzzverrR [31]

Answer: 150 students walk to school

Step-by-step explanation: 75%=0.75

200 multiplied by 0.75

 200×0.75=150 students

            Or

75%=3/4

3/4 of the children walk to school

3/4×200=3/4×200/1=150

4 0
3 years ago
What is the estimation of 5 times 4257
melisa1 [442]
20,000 bc 5 multipled by 4000 which is about 4,257 is 20,000 which gives you a estimation
4 0
4 years ago
Suppose triangle ABC is a right triangle. Side AB is 3 feet and side BC is 4 feet. Find the length of the hypotenuse, AC. Rememb
ElenaW [278]

Answer:

5

Step-by-step explanation:

3 squared + 4 squared = c squared

3 squared= 9   4 squared= 16

9+16=c squared

25=c squared

5= c

7 0
4 years ago
Ill give brainliest please help with this algebra!!
creativ13 [48]

Answer:

Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.

This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.

Take for instance the third question:

\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1

This stands true with all three questions.

HOWEVER

I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple.  Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.

It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.

If that's case, we can solve it the same way we solved question 20.  If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:

\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}

Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent.  If it is instead a coefficient though, then this would be the answer to it.

8 0
3 years ago
Read 2 more answers
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