Answer:
We say this result "terminates" because we found no remainder.
0.123123123.... is an example of a non-terminating fraction.
0.123 123
This fraction is equal to ----------- = --------- = .123123123........
1-0.001 999
Step-by-step explanation:
Answer:
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
Step-by-step explanation:
Given
![$\[x^2 + 22x + \underline{~~~~}.\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20%5Cunderline%7B~~~~%7D.%5C%5D%24)
Required
Fill in the gap
Represent the blank with k
![$\[x^2 + 22x + k\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20k%5C%5D%24)
Solving for k...
To do this, we start by getting the coefficient of x
Coefficient of x = 22
<em />
Divide the coefficient by 2


Take the square of this result, to give k


Substitute 121 for k
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
The expression can be factorized as follows;




<em>Hence, the quadratic expression is </em>
<em></em>
The remainder (which is what Blake says is the remainder), can never be more than the number you are dividing by (the dividend), which in this problem is three.
Divide 136 by 3 and you will prove that answer is incorrect.
A. (x+8)^ 2 + 1
B. (x-3)^ 2 - 8
C. ( x - 3/2) ^ 2 - 1/4