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Alja [10]
3 years ago
15

A line which has an undefined slope is _____.

Mathematics
2 answers:
Len [333]3 years ago
8 0
I think it’s a correct me if I’m wrong
erastovalidia [21]3 years ago
5 0

Answer:

c, vertical

Step-by-step explanation:

blablablablablanlabla

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There are 21 female performers in a dance recital. The ratio of men to women is 4:7. How many men are in the dance recital?
pantera1 [17]

Answer:

12

Step-by-step explanation:

let x be the number of men

4:7 = x:21

4/7 = x/21

7x = 84

x = 12

6 0
3 years ago
What is the area of the rectangle? Round to the nearest square inch.
Mademuasel [1]
Asking the Math Gods...

A=W*L

9*3=27in^2
9*5=45in^2

3 0
3 years ago
What is the slope of a line parallel to the line with equation 5x 3y=7?
adell [148]
-5/3
down 5, over 3
:)
6 0
3 years ago
In ΔDEF, what is sin D, in simplified form?
Igoryamba

Answer: second option.

Step-by-step explanation:

You must apply sin\alpha=\frac{opposite}{hypotenuse}

Then, given the right triangle and the angle D, the opposite side and the hypotenuse of the triangle are the following:

opposite=20\\hypotenuse=25

Therefore, when you substitute values, you have:

sinD=\frac{20}{25}

Reduce the fraction, then you obtain:

 sinD=\frac{4}{5}

5 0
3 years ago
Read 2 more answers
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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