Answer:
the answer is two groups. six times two is 12, 12 is one less than 13 but six cannot go into one
Answer:

Step-by-step explanation:
Given


![Interval: [1,8]](https://tex.z-dn.net/?f=Interval%3A%20%5B1%2C8%5D)

Required
Find c using Intermediate Value theorem
First, check if the value of M is within the given range:







M is within range.
Solving further:
We have:


Substitute 21 for f(x) in 

Express as quadratic function


Expand



or 
or 
The value of
is outside the ![Interval: [1,8]](https://tex.z-dn.net/?f=Interval%3A%20%5B1%2C8%5D)
So:



By comparison:

Total area of land = 1 + 1/2 = 3/2 square miles
Area of square fields = 1/4 x 1/4 = 1/16 square miles
Number of fields = (3/2) / (1/16) = 24 fields.
Answer:
can’t help sorry dude
Step-by-step explanation:
The type of error that occurs if you fail to reject h0 when, in fact, it is not true is a type 2 error.
<h3>What is a type 2 error?</h3>
Type 2 error is when the null hypothesis is not rejected even though it is not false. Type 1 error is when the null hypothesis is rejected when it is true. A type 2 error leads to a false negative which is also known as an error of omission.
To learn more about type 2 error, please check: brainly.com/question/20914617
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