What is the formula for a mid-segment of a triangle
1 answer:
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Answer: a) -7/12 ft/s, -20 ft/s, -7 ft/s
b) 527/24 Ft²/s
c) 2/25 rad/sec
Step-by-step explanation:
a) b=7 ; a^2+b^2 = 25^2
a^2+b^2 = 625
Differentiate w.r.t = 2a (da/dt) + 2b ( db/dt) = 0
As found from above put a=24 b=7,15 and 24. You will get the reuqired answer.
b) Area of the triangle = 1/2 * b*h
differentiate wrt to time leads to the following relation:
c) sin (Θ) = b/25
differentiate it again to give
