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3 years ago

How many pencils in the box are not red?

Mathematics

1 answer:

raketka [301]3 years ago

8 0

The answer is 21 because times the bottom and top by 3 and 2 x 3 is 6 as there are 6 red pencils and 7 x 3 is 21.

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AEFG is located at E (0,0), F (-7, 4), and G (0,8). Which statement correctly classifies AEFG?

viva [34]

Answer:

ΔEFG is an isosceles triangle

Step-by-step explanation:

8 0

3 years ago

The number of employees per department are normally distributed with a population standard deviation of 198 employees and an unk

cricket20 [7]

Answer:

EBM = +-54.126

Step-by-step explanation:

In this question we have confidence interval to be 80%

The formula to solve this is in the attachment.

Bar X = 1460

Z-alpha/2 = 1.282

Sd = standard deviation = 198 employees

n = 22 departments

After we have inserted all values in to the formula we have:

1460 +-(1.282*198/√22)

= 1460+-(54.12604)

= (1405.87, 1514.126)

The error bounded mean EBM

= +-z-alpha/2 x (sd/√n)

= 1.282 x 198/√22

= 1.282 x 42.22

EBM = +-54.126

6 0

3 years ago

Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two

Damm [24]

Answer:

Step-by-step explanation:

Let S be the set of all graphs having vertex set \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

8 0

3 years ago

The probability of choosing 2 green balls without replacement is 11/50 and the probability of choosing one green ball is 12/25.

seraphim [82]

The answer would be 10/75

6 0

3 years ago

List x1, x2, x3, x4 where xi is the midpoint endpoint of the five equal intervals used to estimate the area under the curve of f

Amanda [17]

Answer:

$\bf x_1 = 2\\x_2 = 4\\x_3=6\\x_4=8$

Step-by-step explanation:

The given interval : x = 0 to x = 10

Length of interval = 10 - 0

= 10

$\text{Now, each }x_i \text{ is midpoint and endpoint of the five equal intervals}$

⇒ Number of equal intervals = 5

$\textbf{Length of each interval = }\frac{10}{5}$

$\textbf{Therefore, }\bf x_1 = 0 + 2 = 2\\x_2 = 2 +2 =4\\x_3=4+2=6\\x_4=6+2=8$

3 0

3 years ago