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EastWind [94]
3 years ago
8

Simplify completely the quantity 5 times x to the third power plus 10 times x to the 2nd power plus 15 times x all over 5 times

x. x^2 + 10x^2 + 15x
2^x + 6
x^2 + 2x + 3
x^4 + 2x^3 + 3x^2
Mathematics
2 answers:
Novay_Z [31]3 years ago
4 0
You would factor a 5x out of the numerator sine there is a 5x in 5x^3, 10x^2 and 15x. when you factor, it should be 5x( x^2+2x+3). The 5x on top and bottom would then cancel out, leaving x^2+2x+3 as you answer.
Irina18 [472]3 years ago
3 0
X^2+2x+3 is your answer.
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Find the missing side of the triangle. Side c is the hypotenuse and sides a & b are legs.
dybincka [34]

Answer:

14.05 is as close as I got

Step-by-step explanation:

6.3 squared + b squared = 15.4 squared

6 0
3 years ago
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a ski chalet offers 2 weekend packages. one package provides 2 nights and 3 meals for$280. the other provides 2 nights and 5 mea
Helga [31]


<span> <span>1st</span></span><span> formula 2n + 3m = 280
</span><span><span>
</span><span>2nd</span></span><span> formula 2n + 5m = 320
</span><span><span>
</span><span>rearrange 1st</span> formula to equal n:</span>

    <span><span>2n = -3m + 280
</span>      </span><span>n = -3/2 m + 140
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</span><span>rearrange 2nd</span> formula to equal n:</span>

 <span><span>2n = -5m + 320
</span> </span><span>n = -5/2m + 160
</span><span><span> so now you have

</span>-3/2m + 140 = -5/2m + 160 </span>

<span><span>Rearrange to become:
</span> </span><span><span>-3/2m + 5/2m = 160 - 140
</span> </span><span>m = 20
</span><span>
</span>

<span>Now place 20 into the very 1st</span><span><span> equation in place of the letter m
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</span> </span><span><span>2n + 60 = 280
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</span>so it costs $110 per night, $20 per meal</span>


8 0
4 years ago
The probability that a certain make of car will need repairs in the first seven months is 0.9. A dealer sells three such cars. W
aleksandr82 [10.1K]

Answer:

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

Step-by-step explanation:

For each car, there are only two possible outcomes. Either they will require repair in the first seven months, or they will not. The probability of a car requiring repair in the first seven months is independent of other cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain make of car will need repairs in the first seven months is 0.9.

This means that p = 0.9A dealer sells three such cars.

A dealer sells three such cars.

This means that n = 3

What is the probability that at least one of them will require repairs in the first seven months?

Either none will require repairs, or at least one will. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X > 0) = 1

We want P(X > 0). So

P(X > 0) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.9)^{0}.(0.1)^{3} = 0.001

Then

P(X > 0) = 1 - P(X = 0) = 1 - 0.001 = 0.9990

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

4 0
3 years ago
If p=m and n=16 in the equation m/45 = n/p, what is the value of m?
Andrej [43]
M=p=x
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SEVEN DOLLARS AND TWENTY-FIVE CENTS. ($7.25)

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